# LaTeX update: Read this before posting!

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### #86 alexander

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Posted 19 October 2007 - 03:02 PM

ok, turning this off for now, its acting weird

### #87 alexander

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Posted 19 October 2007 - 03:04 PM

$this^{should}_{render}fine$

### #88 alexander

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Posted 19 October 2007 - 03:06 PM

closer to getting it running right just need to figure out the font size issue.... everything is back to what it used to be before

### #89 Qfwfq

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Posted 20 December 2007 - 04:43 AM

Just hijacking again, for a job purpose...

$\Delta\vec{R}=\vec{R}(\vec{V}+\vec{I}\,)-\vec{R}(\vec{V})$

$\Delta\vec{R}=\vec{R}(\vec{V}+\vec{I})-\vec{R}(\vec{V})$

$f_{\rm c}=-\frac{\vec{R}\cdot\Delta\vec{R}}{\mid\Delta\vec{R}\mid^2}$

$f_{\rm c}=-\frac{\vec{R}\cdot\Delta\vec{R}}{\mid\Delta\vec{R}\mid^2}$

$\vec{V}$

$\vec{V}$

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Posted 20 January 2008 - 11:27 AM

Thank dude

### #91 alexander

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Posted 04 March 2008 - 09:43 AM

I have just figured out that i have forgotten to tell you how to split equations over multiple lines... oooopsie

ok its very simple, for that we need to define a block called split like such:
\begin{split} - start of the block
\end{split} - end of the block
yes, please put in both beginning and end bits of this and don't be lazy

after that you can split ines by using \\
you can also align lines by a symbol by using an ampersand (&) in front of it

\begin{split} \text{These Lines}&-\text{will be aligned}\\ \text{by the}&-\text{dash symbol}\\ &-\text{shazaam}\\ \text{boogie boogie} &- \end{split}

### #92 sanctus

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Posted 05 March 2008 - 01:42 AM

And does align work? I try:
$\begin{split} 2&=1+1 \\ 2&=3+1-2 \\ \end{split}$

### #93 sanctus

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Posted 05 March 2008 - 01:42 AM

well, it doesn't seem to work, have to use split then...

### #94 alexander

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Posted 10 March 2008 - 11:47 AM

no, only split works... i could enable align if there are any benefits to it, granted i actually have that module on the server...

### #95 Qfwfq

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Posted 06 October 2008 - 08:52 AM

How come it gets parsed even when I put it inside code tags?

### #96 alexander

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Posted 06 October 2008 - 09:20 AM

way bb works when it parses... if you do not want it to parse, use the noparse tags

this way you can post
$m_{rel}=\frac{m_0}{\sqrt{1-\frac{v^2}{c^2}}}$
which would render as
$m_{rel}=\frac{m_0}{\sqrt{1-\frac{v^2}{c^2}}}$

ooh better yet
$\begin{split}\Delta P &= \frac{v}{c} \times \frac{E}{2c} \\ 2\Delta P &= v\frac{E}{c^2} \\ P' &= Mv - 2\Delta P = \left(M-\frac{E}{c^2}\right)v \end{split}$

$\begin{split}\Delta P &= \frac{v}{c} \times \frac{E}{2c}\\ 2\Delta P &= v\frac{E}{c^2} \\ P' &= Mv - 2\Delta P = \left(M-\frac{E}{c^2}\right)v \end{split}$

### #97 Qfwfq

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Posted 07 October 2008 - 03:07 AM

thnx

never remember all these tags

### #98 alexander

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Posted 23 February 2009 - 03:57 PM

Ok the main thread LaTeX Formulas: Math v2.0 is updated to the math tag standard, please refer back to it to start figuring stuff out.... (there are many hours put into it)

### #99 Little Bang

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Posted 14 August 2009 - 10:59 AM

$E=Mc^2$

### #100 alexander

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Posted 14 August 2009 - 06:01 PM

Well actually lower case m denotes mass, thus the equivalence is not really valid, and even negating that, its a special case...

$\begin{split}E^2-(pc)^2&=(m_0c^2)^2\\E^2&=(m_0c^2)^2+(pc)^2\\E&=\sqrt{(m_0c^2)^2+(pc)^2}\\E&=c\times\sqrt{(m_0c)^2+p^2}\\\text{where } p=\gamma m_0v\\E&=c\times\sqrt{m_0^2c^2+\gamma ^2m_0^2v^2}\\E&=m_0c\times\sqrt{c^2+\gamma v^2}\end{split}$

### #101 tekayo

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Posted 02 December 2009 - 09:39 AM

great feature that option of click me to see source

### #102 arkain101

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Posted 09 September 2010 - 01:13 PM

Okay so the latex seems to have taken a low blow during the site modifications.