modest Posted January 25, 2009 Report Share Posted January 25, 2009 Oh... ok. I was looking at the /frac at the bottom of your post where it asks why it's not rendering. I didn't see the one at the top. testing...[math]\frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28} = 2[/math] [math]\frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28} = 2[/math] why is [math]/frac{1}{14}[/math] not rendering right using the latex tags instead of math tags? :confused:I've noticed, though I have no explanation for this, latex tags need spaces where math tags do not. So I'm guessing... [math]\frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28} = 2[/math] [math]\frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+ \frac{1}{14}+\frac{1}{28} = 2[/math] Yeah, a space before the "\frac{1}{14}" fixed it. To prevent it rendering you can use [noparse][/noparse] tags... [math]\frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+ \frac{1}{14}+\frac{1}{28} = 2[/math] Sorry 'bout the confusion. ~modest Quote Link to comment Share on other sites More sharing options...

alexander Posted January 26, 2009 Author Report Share Posted January 26, 2009 why are you guys using the latex tags???!!!??? DEAR PEOPLE!!! It has come to my attention that you are still using the latex tags, even though they have been deprecated and outdated for quite some time now. I actually left the old engine on to support antiquated syntax in posts, but apparently some people STILL use it! Stop using the latex tags, they are deprecated and use far more resources then the math tags, simply because they don't do any caching!!! Quote Link to comment Share on other sites More sharing options...

Turtle Posted January 26, 2009 Report Share Posted January 26, 2009 why are you guys using the latex tags???!!!??? I can only speak for myself, but I used them because I'm a noobus :eek2:, and the title of the thread was Latex Practice Ground not Math Practice Ground. Do I take my shirt off, or leave it on for my lashes? :) Quote Link to comment Share on other sites More sharing options...

JMJones0424 Posted February 23, 2009 Report Share Posted February 23, 2009 [math]u = \frac{v_1 + v_2}{1 + \frac{(v_1 \times v_2)}{c^2}}[/math] Quote Link to comment Share on other sites More sharing options...

freeztar Posted February 23, 2009 Report Share Posted February 23, 2009 [math]u = \frac{v_1 + v_2}{1 + (v_1 * v_2)c^2}[/math] Well done Jones! :)Another good tag to know is the multiply sign (it looks better than an asterisk). ;) [math]3\times4[/math][math]3\times4[/math] or [math]3\cdot4[/math][math]3\cdot4[/math] Quote Link to comment Share on other sites More sharing options...

alexander Posted February 23, 2009 Author Report Share Posted February 23, 2009 shoot i forgot to finish the updated tutorial... Quote Link to comment Share on other sites More sharing options...

alexander Posted February 23, 2009 Author Report Share Posted February 23, 2009 oh pheew, i almost did... btw no comments on the updated tutorial? Quote Link to comment Share on other sites More sharing options...

alexander Posted February 23, 2009 Author Report Share Posted February 23, 2009 updated a little more today to provide explanations for some math symbols, etc... only things left are widehat, widetilde, and finally to figure out what Pr function is... Quote Link to comment Share on other sites More sharing options...

modest Posted February 24, 2009 Report Share Posted February 24, 2009 Looks fantastically helpful to me. :thumbs_up I did notice one small thing, \widetilde{abc} [math]\overwidetilde{abc}[/math]\widehat{abc} [math]\overwidehat{abc}[/math] A bit over wide :hihi: But, really, all-around fantastic. ~modest Quote Link to comment Share on other sites More sharing options...

alexander Posted February 24, 2009 Author Report Share Posted February 24, 2009 yea i gotta solve those issues... i'll get around to it hopefully tomorrow Quote Link to comment Share on other sites More sharing options...

modest Posted May 31, 2009 Report Share Posted May 31, 2009 [ce]6FeO -> 2Fe2O3 + 2Fe[/ce][ce]6FeO -> 2Fe_2O_3 + 2Fe[/ce][ce]6 FeO -> 2 Fe_2 O_3 + 2 Fe[/ce][ce]6FeO \rightarrow 2Fe_2O_3 + 2Fe[/ce][ce]FeO -> Fe2O3 + Fe[/ce][ce]FeO -> FeO + Fe[/ce][ce]FeO[/ce][ce]Fe[/ce][ce]Se[/ce][ce]H[/ce][ce]Na[/ce] :confused: I'm at a loss Quote Link to comment Share on other sites More sharing options...

alexander Posted May 31, 2009 Author Report Share Posted May 31, 2009 somebody messed with something in the plugin again, or someone played with the latex install, i gotta get to tormod, i noticed the ce tags were going crazy things too... Let me find out what has changed, but something certainly did... Quote Link to comment Share on other sites More sharing options...

rish209 Posted June 9, 2012 Report Share Posted June 9, 2012 (edited) ;$e=mc^2$WHY WONT LATEX WORK Edited June 9, 2012 by rish209 Quote Link to comment Share on other sites More sharing options...

CraigD Posted June 9, 2012 Report Share Posted June 9, 2012 ;$e=mc^2$WHY WONT LATEX WORK'Cause, on forums like ours, you don't tag it with $...;, but [math]...[/math] or [imath]...[/imath]. So [math]e=mc^2[/math] renders as [math]e=mc^2[/math]. Quote Link to comment Share on other sites More sharing options...

phision Posted June 10, 2012 Report Share Posted June 10, 2012 So [math]e=mc^2[/math] renders as [math]e=mc^2[/math]. Was going to ask why the phrase you entered above wasn't rendered, but after seeing the quote I understand now. Quote Link to comment Share on other sites More sharing options...

rhertz Posted May 22, 2019 Report Share Posted May 22, 2019 (edited) [math] \frac{\dot{T}}{T} (\frac{\ddot{T}}{T} + \frac{kc^2}{a^2}) = \frac{8 \pi G}{3} \int\ [\dot{N} + N\dot{S}_k + N\dot{S}_{ik}] (\frac{8 \pi \hbar \nu^3}{c^3} \frac{1}{\frac{\hbar \nu}{k_BT} - 1} + \frac{8 \pi \hbar \nu^3}{2c^3})\ d\nu[/math] text to separate [math] ab_0 [/math][math] a [/math][math] a [/math][math] ac^2 [/math][math] k^2 = a^2 [/math][math] ab_0 [/math] [math] {\large{\int_{k=0}^{55}}} k dk [/math] [math] \int_{k=0}^{55} k dk [/math] [math] I(t) = I_0.e^{-\large\frac {t}{\tau_0}} [/math] [math] \Gamma_\mu = \large\frac {G_F^2{m_\mu}^5}{192\pi^3} [/math] [math] \tau_\mu = \large\frac {\hbar}{\Gamma_\mu} [/math] [math] \tau_\mu = 6 [\math] [math] \tau_\mu = \large\frac {192\hbar\pi^3}{G_F^2{m_\mu}^5}[\math] Edited May 25, 2019 by rhertz Quote Link to comment Share on other sites More sharing options...

fahrquad Posted May 26, 2019 Report Share Posted May 26, 2019 What is there to practice with latex? You either get it right or you make child support payments for the next 18 years. Quote Link to comment Share on other sites More sharing options...

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