Mercedes Benzene Posted May 13, 2007 Report Share Posted May 13, 2007 Just testing out some Latex since I've never really used it before! [math]t=\frac {\bar{x}-\mu}{s/sqrt{n} [/math] [math] 7.77 \pm 1.984\left(\frac{2.28956}{\sqrt{100}}\right) [/math] [math] (7.316,8.224) [/math] Quote Link to comment Share on other sites More sharing options...

DougF Posted May 31, 2007 Report Share Posted May 31, 2007 f(x)=int_{-infty}^xfrac{(e^{-t^2})}{sqrt{pi^x}}dt Quote Link to comment Share on other sites More sharing options...

DougF Posted May 31, 2007 Report Share Posted May 31, 2007 f(x)=int_{-infty}^xfrac{(e^{-t^2})}{sqrt{pi^x}}dt[tag]f(x)=int_{-infty}^xfrac{(e^{-t^2})}{sqrt{pi^x}}dt[/tag] Quote Link to comment Share on other sites More sharing options...

DougF Posted May 31, 2007 Report Share Posted May 31, 2007 [tag]f(x)=int_{-infty}^xfrac{(e^{-t^2})}{sqrt{pi^x}}dt[/tag][tag] f(x)=int_{-infty}^xfrac{(e^{-t^2})}{sqrt{pi^x}}dt [/tag] I think i'm missing somethe here? Quote Link to comment Share on other sites More sharing options...

DougF Posted May 31, 2007 Report Share Posted May 31, 2007 I guess I'm not holding my mouth right. Quote Link to comment Share on other sites More sharing options...

Mercedes Benzene Posted May 31, 2007 Report Share Posted May 31, 2007 You don't use [tag], you use THE tags latex and /latex Quote Link to comment Share on other sites More sharing options...

DougF Posted May 31, 2007 Report Share Posted May 31, 2007 Thanks I'll try one more time! :eek_big: [math] f(x)=\int_{-\infty}^x\frac{(e^{-t^2})}{\sqrt{\pi^x}}dt [/math] Thanks: I think I've got it now. :doh: RED Quote Link to comment Share on other sites More sharing options...

alexander Posted September 10, 2007 Author Report Share Posted September 10, 2007 [math]f(x)=\int_{-\infty}^x\frac{(e^{-t^2})}{\sqrt{\pi^x}}dt[/math] Quote Link to comment Share on other sites More sharing options...

CraigD Posted October 7, 2007 Report Share Posted October 7, 2007 A Feynman diagram, without the pretty wavy line... [math] setlength{unitlength}{1mm} begin{picture}(0, 0) put(10, 20){ makebox(3,0)[cc]{$gamma$} vector(1,0){10} } put(24, 20){ vector(2,1){10} } put(24, 20){ vector(2,-1){10} } put(35, 25){ makebox(3,0)[cc]{$e^-$} vector(2,-1){10} } put(35, 15){ makebox(3,0)[cc]{$e^+$} vector(2,1){10} } put(50, 20){ makebox(3,0)[cc]{$gamma$} vector(1,0){10} } end{picture} [/math] Quote Link to comment Share on other sites More sharing options...

tierradelfuego Posted October 10, 2007 Report Share Posted October 10, 2007 [math]-1 = e^{\pi i}[/math] Quote Link to comment Share on other sites More sharing options...

alexander Posted October 10, 2007 Author Report Share Posted October 10, 2007 please use the the math tags.... instead of [math]-1=e^{\Pi i}[/math][math]-1=e^{\pi i}[/math] use [math]-1=e^{\Pi i}[/math][math]-1=e^{\pi i}[/math] distinct advantages of the second over the first are:you can now click on the expression to see the codeyou can notice better rendering and space managementyou can now do a load more with this then you were able to with latex... you can do stuff like this:[math]I(z) = \sin( \frac{\pi}{2} z^2 ) \sum_{n=0}^\infty\frac{ (-1)^n \pi^{2n} }{1 \cdot 3\cdots (4n + 1) } z^{4n + 1}-\cos( \frac{\pi}{2} z^2 ) \sum_{n=0}^\infty\frac{ (-1)^n \pi^{2n + 1} }{1 \cdot 3\cdots (4n + 3) } z^{4n + 3}[/math] [math]\setlength{\unitlength}{1mm}\begin{picture}(60, 40){\put(30, 20){\vector(1, 0){30}}}{\put(30, 20){\vector(4, 1){20}}}{\put(30, 20){\vector(3, 1){25}}}{\put(30, 20){\vector(2, 1){30}}}{\put(30, 20){\vector(1, 2){10}}}\thicklines\put(30, 20){\vector(-4, 1){30}}\put(30, 20){\vector(-1, 4){5}}\thinlines\put(30, 20){\vector(-1, -1){5}}\put(30, 20){\vector(-1, -4){5}}\end{picture}[/math] i gotta go find if i can enable the pst-plot module.... that would be interesting Quote Link to comment Share on other sites More sharing options...

snoopy Posted December 18, 2007 Report Share Posted December 18, 2007 testing [math]f(x)=\int_{-\infty}^x\frac{(e^{-t^2})}{\sqrt{\pi^x}}dt[/math] Ah I see.... said the blind man Quote Link to comment Share on other sites More sharing options...

snoopy Posted December 21, 2007 Report Share Posted December 21, 2007 [math]\fontsize=10\setlength{\unitlength}{1mm}\begin{picture}(60,40)\end{picture}[/math] [math]y=mx+c[/math] Quote Link to comment Share on other sites More sharing options...

snoopy Posted December 21, 2007 Report Share Posted December 21, 2007 Quote Link to comment Share on other sites More sharing options...

pigeon_soup Posted June 12, 2008 Report Share Posted June 12, 2008 frac{dy}{dy} = fract {9}{32} (x^2 -4x) Quote Link to comment Share on other sites More sharing options...

pigeon_soup Posted June 12, 2008 Report Share Posted June 12, 2008 frac{dy}{dy} = fract {9}{32} (x^2 -4x) Quote Link to comment Share on other sites More sharing options...

CraigD Posted June 12, 2008 Report Share Posted June 12, 2008 [math]\frac{dy}{dy} = \fract {9}{32} (x^2 -4x)[/math] doesn't parse correctly due to the unrecognized element "fract":[math]\frac{dy}{dy} = \fract {9}{32} (x^2 -4x)[/math] [math]\frac{dy}{dy} = \frac{9}{32} (x^2 -4x)[/math] renders as:[math]\frac{dy}{dy} = \frac{9}{32} (x^2 -4x)[/math] There's also an older tag, [math], but it renders less nicely, and supports less LaTeX than the [math] tag. Using LaTeX in your posts shows attention to detail, which will win the admiration of your peers! :) Quote Link to comment Share on other sites More sharing options...

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