Jump to content
Science Forums

Pi


Recommended Posts

Here's an interesting problem for the math whizzes here: how many decimal places do you need to compute Pi to in order to be able to accurately compute the circumference of the *visible* universe to +/- 1cm? Describe and justify your answer....

 

Computadora,

Buffy

Link to comment
Share on other sites

Here's an interesting problem for the math whizzes here: how many decimal places do you need to compute Pi to in order to be able to accurately compute the circumference of the *visible* universe to +/- 1cm? Describe and justify your answer....

It's a trick question... it hasn't been proven that the universe is spherical. :confused:

Link to comment
Share on other sites

It's a trick question... it hasn't been proven that the universe is spherical. :confused:
Actually its *not* a trick question: Note I was very specific about saying the "visible universe" which by definition is the sphere described from our location by the Hubble Limit. It really is mostly a *math* problem! Get out your thinking caps boys and girls! :shrug:

 

Crunch, cruch,

Buffy

Link to comment
Share on other sites

how many decimal places do you need to compute Pi to in order to be able to accurately compute the circumference of the *visible* universe to +/- 1cm? Describe and justify your answer....

 

It's a trick question... it hasn't been proven that the universe is spherical.

 

Actually its *not* a trick question: Note I was very specific about saying the "visible universe" which by definition is the sphere described from our location by the Hubble Limit.

 

Well, in that case...

 

The more decimal places you have, the more accurate your answer. Pretty simple really. Three decimal places? Not as accurate as 3 google decimal places... :eek_big:

 

 

Cheers. :hihi:

Link to comment
Share on other sites

Well, in that case...

 

The more decimal places you have, the more accurate your answer. Pretty simple really. Three decimal places? Not as accurate as 3 google decimal places... :eek_big:

 

 

Cheers. :hihi:

 

But...at what point will the addition of digits stop making a difference? At the 100,000th or the 1 millionth? It's an interesting question.

Link to comment
Share on other sites

But...at what point will the addition of digits stop making a difference? At the 100,000th or the 1 millionth? It's an interesting question.

While diminishing returns will be a factor, does it not remain true that the addition of another decimal point will still increase the accuracy ad infinitum? :eek_big:

 

 

:hihi:

Link to comment
Share on other sites

What are we here, sophists?! Buffy asks a straightforward (and not very difficult) question, deserving a straightforward answer.

Here's an interesting problem for the math whizzes here: how many decimal places do you need to compute Pi to in order to be able to accurately compute the circumference of the *visible* universe to +/- 1cm? Describe and justify your answer....
You need only compute Pi to the 29th decimal place to accurately compute the circumference of the *visible* universe to +/- 1cm.

 

Assume a radius r of the visible universe of about 13.7 billion (1.37*10^10) light years.

The circumference ctrue of the visible universe is then 2 * Pi * r.

An inaccurate circumference cerror is 2 * (Pi + errorPi) *r.

Given cerror = .01 m, converting and solving for errorPi, gives

errorPi = cerror /(2 * r) = about 1.5 *10^-29

 

So an estimate of Pi within 1.5 *10^-29 of its true value will result in cerror < .01 m.

Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
×
×
  • Create New...