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Triangle mystery


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I received this puzzle a few day ago and I have no clue about the answer. After shifting the inner blocks of the triangle to form a new and identical triangle one block is missing. I still get a triangle but with one block less. How can this be?

 

EDIT: File replaced by Tormod to reduce filesize. Original was 500K!!!

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I have not seen this before, but one problem that comes up when looking at this diagram, is that if you find the total area of the large triange:

 

1/2(bh)= 1/2(13X5)=32.5 square units.

 

When the tiangle is broken up into sub units the sum of the areas = 32 square units on both triangle neglecting the "hole".

 

If one were to put the two tiangles together to form a rectangle, you would have an area:

 

Area=bh = 13X5=65 square units.

 

The sum of the sub-units in the triangles would equal 64 square units and your missing square would total up to 65 square units.

:hyper:

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It looks like some subtle fudging in the drawing of the two specimens. The hypotenuse of the bottom specimen is bowed ever-so-slightly outward, while the opposite is true of the top one. You can detect this by where the upper left corner of the #4 piece touches the hypotenuse in the bottom drawing, and compare that to the same locale in the top drawing.

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The slopes of the two smaller triangles aren't the same - one is 3/8, one is 2/5 - there is no way that they could form a triangle.
Precisely what I found as well! Hence my answer in post #3 above was the correct one: the hypotenuse bulges somewhat in the lower drawing, and is a tad concave on the top specimen. :hyper:

 

Afterthought: that puzzle is one of the kewlest tantalizers ever!!!

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Looks to me as if the angled side of the triangle is slightly bowed in, thus the slopes are slightly different. That's why the two triangles, when switched, form a different slope. I bet that's where the extra space comes from, the difference in the non-linear edge

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