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Cut The Bullshit In Physics


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#324 Dubbelosix

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Posted 05 June 2019 - 04:54 PM

Dubbelosix, I wanted you to know that I'm putting you in my Ignore List once I finish this post.

 

I don't want to trigger you or hurt in anyway your feelings, so I consider that this is the best thing to do.

 

First time ever that I use this feature.

 

Absolutely, be my guest. I welcome it.



#325 Dubbelosix

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Posted 05 June 2019 - 04:56 PM

You will find such peace but resist peeking, the people here have nothing important to say now or in the future.

 

It's like an impulsion with you people... Haven't you listened to the mods? And now here is me eating the bait. 



#326 VictorMedvil

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Posted 05 June 2019 - 04:57 PM

No more bullshit shall be cut, Mods close my thread.

 

franken-stein-u3.png


Edited by VictorMedvil, 05 June 2019 - 05:03 PM.

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#327 Dubbelosix

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Posted 05 June 2019 - 05:00 PM

On the contrary, you keep asking people to varify with explanations why you are wrong, while I left you wordless?

 

 

I think I left you worthless, to be honest. 

 

Well, this is the last time I answer you, because you let me wordless.



#328 ralfcis

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Posted 05 June 2019 - 06:37 PM

Marco I've already answered your question but since you are illiterate in math you can't understand the answer. However, I'll give it another shot on my relativity and algebra thread because I'd like to keep things in one place for the future. 



#329 sluggo

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Posted 08 June 2019 - 12:01 PM

rhertz#308;

Let's examine the chase scene. The morons rob a bank, and speed away at 50 mph on route 66. The police get a call of a sighting 1 mile away. They immediately speed after them at 60 mph. How long will it take to catch up with the robbers?
distance between cars = 1, robber car speed r = 50, cop car speed c = 60, d = distance.
For robbers, d=1 + rt.
For cops, d=ct.
If cops and robbers are coincident, then 1+rt = ct.
Rearranging, t(c-r)=1, and t=1/(c-r).
Note, nothing is moving at a speed of (c-r)!
There are two objects in motion, so both speeds are required to solve the problem.
Transfer this relationship to an SR example.
A stick 1 unit long with a light at the near end and a mirror at the far end, moves at v along x. A photon moves at c toward the mirror. Using the same setup for the 1st example, t1=1/(c-v). For the reflection, t2 = 1/(c+v).
Nothing moves at (c-v) or (c+v).
Those two values are referred to as 'closing speeds'. How long to form or close a spatial gap/interval.



#330 GAHD

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Posted 09 June 2019 - 07:25 PM

No more bullshit shall be cut, Mods close my thread.

 

MMK.

To those interested, you can still copypasta a reply quote in a new thread if you're so inclined.