HarlanHill Posted May 26 Report Share Posted May 26 Hi friends! I got the following assignment in college. In parallelogram PQSR, what is PQ? (2x + 5) cm a) 2 cm b) 5 cm c) 6 cm d) 9 cm I will be very grateful for your help in solving it. Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted May 27 Report Share Posted May 27 Hi Harlan ðŸ‘‹Â Â this problem takes me back to basics. One of the most simple problems was to get rise over run of -5/2 and when you have PQ in that sort of parallelogram with sums 2.5 obvs itâ€™s 5 or b) Quote Link to comment Share on other sites More sharing options...

OceanBreeze Posted May 28 Report Share Posted May 28 On 5/27/2022 at 11:49 AM, JeffreysTubes8 said: Hi Harlan ðŸ‘‹Â Â this problem takes me back to basics. One of the most simple problems was to get rise over run of -5/2 and when you have PQ in that sort of parallelogram with sums 2.5 obvs itâ€™s 5 or b) Back to basics is where you belong. Your answer is silly. Quote Link to comment Share on other sites More sharing options...

OceanBreeze Posted May 28 Report Share Posted May 28 On 5/26/2022 at 5:07 PM, HarlanHill said: Hi friends! I got the following assignment in college. In parallelogram PQSR, what is PQ? (2x + 5) cm a) 2 cm b) 5 cm c) 6 cm d) 9 cm I will be very grateful for your help in solving it. In parallelogram PQSR, what is PQ? You have only given us the fact that PQ = (2x + 5) cm That is not enough information to solve the problem. You must also give the value of RS. We know that opposite sides of a parallelogram are equal in magnitude. So, PQ = RS and PR = QS A typical problem statement might be PQ = (2x + 5) cm and RS = (4x + 1) solve for PQ Then, since PQ = RS The solution is very simple: 2X + 5 = 4x + 1 Then, 5 = 2x + 1 and 2X = 4 x = 2, so 2x + 5 = 9 cm side PQ = 9 cm Ans. It is a very simple problem when you provide all of the information! Â Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted May 29 Report Share Posted May 29 (edited) 22 hours ago, OceanBreeze said: In parallelogram PQSR, what is PQ? You have only given us the fact that PQ = (2x + 5) cm That is not enough information to solve the problem. You must also give the value of RS. We know that opposite sides of a parallelogram are equal in magnitude. So, PQ = RS and PR = QS A typical problem statement might be PQ = (2x + 5) cm and RS = (4x + 1) solve for PQ Then, since PQ = RS The solution is very simple: 2X + 5 = 4x + 1 Then, 5 = 2x + 1 and 2X = 4 x = 2, so 2x + 5 = 9 cm side PQ = 9 cm Ans. It is a very simple problem when you provide all of the information! Â You misunderstood PQ is not 2x+5 cm thatâ€™s the y-intercept formulaÂ y=mx+b Â Edited May 29 by JeffreysTubes8 Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted May 29 Report Share Posted May 29 (edited) 1 hour ago, JeffreysTubes8 said: You misunderstood PQ is not 2x+5 cm thatâ€™s the y-intercept formulaÂ y=mx+b Â That means if x=2 then y=9, 9/2 is 4.5, so yeah itâ€™s 9 if x = 2.Â Edited May 29 by JeffreysTubes8 Quote Link to comment Share on other sites More sharing options...

## Recommended Posts

## Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.