TonyYuan2020 Posted March 18, 2020 Author Report Posted March 18, 2020 (edited) On 3/18/2020 at 1:14 PM, VictorMedvil said: You are following the same path as ralfcis, ralfcis already asked this question in (http://www.scienceforums.com/topic/35098-relativity-and-simple-algebra/). The answer is your add the gamma's to find the speed or use the equation r2 = x2 + y2 + z2 1) A and B are traveling at γa * γb or it's around like .995C2) They are again traveling γa * γb or like 0C3) They are traveling at γf2 = γx2 + γy2 or .933CCan you explain the calculation process of 0.933C? What's the specific data? Janus told me it is like this w = (u+v)/(1+uv/c^2), You told me it is γf2 = γx2 + γy2 Edited March 18, 2020 by TonyYuan2020 Quote
Vmedvil2 Posted March 18, 2020 Report Posted March 18, 2020 On 3/18/2020 at 1:29 PM, TonyYuan2020 said: Can you explain the calculation process of 0.933C? What's the specific data?Use algebra, it's just substitution. Quote
TonyYuan2020 Posted March 18, 2020 Author Report Posted March 18, 2020 (edited) On 3/18/2020 at 1:31 PM, VictorMedvil said: Use algebra, it's just substitution.Can you write down the specific operation steps? This is very important.Janus told me it is like this w = (u+v)/(1+uv/c^2), You told me it is γf2 = γx2 + γy2 Edited March 18, 2020 by TonyYuan2020 Quote
Vmedvil2 Posted March 18, 2020 Report Posted March 18, 2020 On 3/18/2020 at 1:33 PM, TonyYuan2020 said: Can you write down the specific operation steps? This is very important.Janus told me it is like this w = (u+v)/(1+uv/c^2), You told me it is γf2 = γx2 + γy2They both yield the same answer. Quote
TonyYuan2020 Posted March 18, 2020 Author Report Posted March 18, 2020 (edited) On 3/18/2020 at 1:35 PM, VictorMedvil said: They both yield the same answer.Can you write down the specific operation steps? This is very important. w = (u+v)/(1+uv/c^2), here u=? v=? Janus's answer of first question: (0.9c+0.9c)/(1+ 0.9c(0.9c)/c^2) = ~0.9945cwhen i ask second question, he hasn't given an answer yet. Third question:Your answer is 0.933C, can you write out the calculation process? Edited March 18, 2020 by TonyYuan2020 Quote
Vmedvil2 Posted March 18, 2020 Report Posted March 18, 2020 (edited) On 3/18/2020 at 1:37 PM, TonyYuan2020 said: Can you write down the specific operation steps? This is very important. w = (u+v)/(1+uv/c^2), here u=? v=? u = Vx , v = Vy , I just annotated them dimensionally instead in a (u,v) matrix which is the samething. Edited March 18, 2020 by VictorMedvil Quote
TonyYuan2020 Posted March 18, 2020 Author Report Posted March 18, 2020 (edited) On 3/18/2020 at 1:39 PM, VictorMedvil said: u = Vx , v = Vy , I just annotated them dimensionally instead in a (u, v) matrix which is the samething.u=0.9C or -0.9C or others?v=0.9C or -0.9C or others?w = (u+v)/(1+uv/c^2) = (?+?)(1+??/c^2) Edited March 18, 2020 by TonyYuan2020 Quote
Vmedvil2 Posted March 18, 2020 Report Posted March 18, 2020 On 3/18/2020 at 1:42 PM, TonyYuan2020 said: u=0.9C or -0.9C or others?v=0.9C or -0.9C or others?w = (u+v)/(1+uv/c^2) = (?+?)(1+??/c^2) u = .9Cv = .9CVx = .9CVy = .9C Quote
TonyYuan2020 Posted March 18, 2020 Author Report Posted March 18, 2020 On 3/18/2020 at 1:44 PM, VictorMedvil said: u = .9Cv = .9CVx = .9CVy = .9CJanus's answer for first answer: Thus w( the relative velocity between ship A and B as measured by either ship) is(0.9c+0.9c)/(1+ 0.9c(0.9c)/c^2) = ~0.9945c = 0.994475138121547C but your answer is 0.933C ,why? Quote
Vmedvil2 Posted March 18, 2020 Report Posted March 18, 2020 On 3/18/2020 at 1:49 PM, TonyYuan2020 said: Janus's answer for first answer: Thus w( the relative velocity between ship A and B as measured by either ship) is(0.9c+0.9c)/(1+ 0.9c(0.9c)/c^2) = ~0.9945c = 0.994475138121547C but your answer is 0.933C ,why?It was a typo, it was .994, i just rounded incorrectly. Quote
TonyYuan2020 Posted March 18, 2020 Author Report Posted March 18, 2020 (edited) On 3/18/2020 at 1:50 PM, VictorMedvil said: It was a typo, it was .994, i just rounded incorrectly. First scene:<--A----------------------------------Earth---------------------------------------B--->-0.9C............................................................................................................0.9CPlease answer the relative speed between A and B . Victor's answer is 0.9945C. Second scene:Earth---------------------------------------A--->----------------------------------------------B--->.............................................................0.9CPlease answer the relative speed between A and B . Victor's answer is 0C. Third scene:Earth---------------------------------------A--->.|....................................................0.9C.|.|.|.|\/ B 0.9CPlease answer the relative speed between A and B . Victor's answer is 0.9945C. Fourth scene:Earth---------------------------------------A--->.。|....................................................0.9C.。。|.。。。|.。。。。|.。。。。。|..................._/ B 0.9C The angle is 45 degreesPlease answer the relative speed between A and B . Edited March 18, 2020 by TonyYuan2020 Quote
Vmedvil2 Posted March 18, 2020 Report Posted March 18, 2020 (edited) On 3/18/2020 at 1:57 PM, TonyYuan2020 said: First scene:<--A----------------------------------Earth---------------------------------------B--->-0.9C............................................................................................................0.9CPlease answer the relative speed between A and B . Victor's answer is 0.9945C. Second scene:Earth---------------------------------------A--->----------------------------------------------B--->.............................................................0.9CPlease answer the relative speed between A and B . Victor's answer is 0C. Third scene:Earth---------------------------------------A--->.|....................................................0.9C.|.|.|.|\/ B 0.9CPlease answer the relative speed between A and B . Victor's answer is 0.9945C. Fourth scene:Earth---------------------------------------A--->.。|....................................................0.9C.。。|.。。。|.。。。。|.。。。。。|..................._/ B 0.9C The angle is 45 degreesPlease answer the relative speed between A and B . You aren't going to get different answers the more complex you make it, special relativity is correct. I don't feel like doing that situation as it would require doing alot of alegbra to find the velocities between those object as you would have to take in account alot of trigonometry, but something like this γf = (γax - γbx(component))2 + γby(component)2 Edited March 18, 2020 by VictorMedvil Quote
TonyYuan2020 Posted March 18, 2020 Author Report Posted March 18, 2020 On 3/18/2020 at 2:02 PM, VictorMedvil said: You aren't going to get different answers the more complex you make it, special relativity is correct. I don't feel like doing that situation as it would require doing alot of alegbra to find the velocities between those object as you would have to take in account alot of trigonometry. Third scene:Earth---------------------------------------A--->.|....................................................0.9C.|.|.|.|\/ B 0.9CPlease answer the relative speed between A and B . Victor's answer is 0.9945C. But According to special relativity, the answer should be u=21/2/2 * 0.9c, v=21/2/2 * 0.9c, the last answer is 0.906C. Quote
Vmedvil2 Posted March 18, 2020 Report Posted March 18, 2020 (edited) On 3/18/2020 at 2:22 PM, TonyYuan2020 said: Third scene:Earth---------------------------------------A--->.|....................................................0.9C.|.|.|.|\/ B 0.9CPlease answer the relative speed between A and B . Victor's answer is 0.9945C. But According to special relativity, the answer should be u=21/2/2 * 0.9c, v=21/2/2 * 0.9c, the last answer is 0.906C. Like I have said many times Newtonian physics is wrong, learn to stop using it, those aren't velocities they are Gammas γ. Edited March 18, 2020 by VictorMedvil Quote
TonyYuan2020 Posted March 18, 2020 Author Report Posted March 18, 2020 On 3/18/2020 at 2:24 PM, VictorMedvil said: Like I have said many times Newtonian physics is wrong, learn to stop using it, those aren't velocities they are Gammas γ.According to this theory, A and B go far away from each other. With A as the reference, B's time goes slower, and with B as the reference, A's time goes slower. We'll never know who's slower. When they meet, please tell me whose time is slower? Crazy relativity. Quote
Vmedvil2 Posted March 18, 2020 Report Posted March 18, 2020 On 3/18/2020 at 2:38 PM, TonyYuan2020 said: According to this theory, A and B go far away from each other. With A as the reference, B's time goes slower, and with B as the reference, A's time goes slower. We'll never know who's slower. When they meet, please tell me whose time is slower? Crazy relativity.I am done with you crank, go bother someone else. Quote
TonyYuan2020 Posted March 18, 2020 Author Report Posted March 18, 2020 (edited) On 3/18/2020 at 2:24 PM, VictorMedvil said: Like I have said many times Newtonian physics is wrong, learn to stop using it, those aren't velocities they are Gammas γ. I'll give Janus the last shot in a minute. I'm waiting for his YES. Edited March 18, 2020 by TonyYuan2020 Quote
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.