Science Forums

# Doppler Effect Of Gravitational Field

## Recommended Posts

I don't know what your talking about you are obviously delusional, I solved it then they solved it using special relativity(http://www.scienceforums.com/topic/36528-questions-to-special-relativity and http://www.sciforums.com/threads/a-story-about-special-relativity-who-can-explain-it%EF%BC%9F.162954/).

First scene:

<--A----------------------------------Earth---------------------------------------B--->

-0.9C............................................................................................................0.9C

Second scene:

Earth---------------------------------------A--->

----------------------------------------------B--->

.............................................................0.9C

Third scene:

Earth---------------------------------------A--->

.|....................................................0.9C

.|

.|

.|

.|

\/ B 0.9C

• Replies 152
• Created

#### Popular Posts

Time to move this to alternate theories.

I don't judge a thing in general as right or wrong. I will analyze and ask questions one by one, waiting for the other party to answer.OK, let's continue to discuss it in depth. I hope our discussion

I did notice your red stamp in this thread.   I didn't remove it. :)

#### Posted Images

Posted (edited)

First scene:

<--A----------------------------------Earth---------------------------------------B--->

-0.9C............................................................................................................0.9C

Second scene:

Earth---------------------------------------A--->

----------------------------------------------B--->

.............................................................0.9C

Third scene:

Earth---------------------------------------A--->

.|....................................................0.9C

.|

.|

.|

.|

\/ B 0.9C

You are following the same path as ralfcis, ralfcis already asked this question in (http://www.scienceforums.com/topic/35098-relativity-and-simple-algebra/). The answer is your add the gamma's to find the speed or use the equation r= x+ y+ z2

1) A and B are traveling at γaγ or it's around like .995C

2) They are again traveling γa * γb or like 0C

3) They are traveling at γfγx2 + γy2   or ‭.994C

Edited by VictorMedvil
##### Share on other sites
Posted (edited)

You are following the same path as ralfcis, ralfcis already asked this question in (http://www.scienceforums.com/topic/35098-relativity-and-simple-algebra/). The answer is your add the gamma's to find the speed or use the equation r= x+ y+ z2

1) A and B are traveling at γaγ or it's around like .995C

2) They are again traveling γa * γb or like 0C

3) They are traveling at γfγx2 + γy2   or ‭.933C

Can you explain the calculation process of ‭ 0.933C? What's the specific data?

Janus told me it is like this  w = (u+v)/(1+uv/c^2),  You told me it is γfγx2 + γy2

Edited by TonyYuan2020
##### Share on other sites

Can you explain the calculation process of ‭ 0.933C? What's the specific data?

Use algebra, it's just substitution.

##### Share on other sites
Posted (edited)

Use algebra, it's just substitution.

Can you write down the specific operation steps? This is very important.

Janus told me it is like this  w = (u+v)/(1+uv/c^2),  You told me it is γfγx2 + γy2

Edited by TonyYuan2020
##### Share on other sites

Can you write down the specific operation steps? This is very important.

Janus told me it is like this  w = (u+v)/(1+uv/c^2),  You told me it is γfγx2 + γy2

They both yield the same answer.

##### Share on other sites
Posted (edited)

They both yield the same answer.

Can you write down the specific operation steps? This is very important.

w = (u+v)/(1+uv/c^2), here u=? v=?

Janus's answer of first question: (0.9c+0.9c)/(1+ 0.9c(0.9c)/c^2) = ~0.9945c

Third question:

Edited by TonyYuan2020
##### Share on other sites
Posted (edited)

Can you write down the specific operation steps? This is very important.

w = (u+v)/(1+uv/c^2), here u=? v=?

u = Vx , v = V, I just annotated them dimensionally instead in a (u,v) matrix which is the samething.

Edited by VictorMedvil
##### Share on other sites
Posted (edited)

u = Vx , v = V, I just annotated them dimensionally instead in a (u, v) matrix which is the samething.

u=0.9C or -0.9C or others?

v=0.9C or -0.9C or others?

w = (u+v)/(1+uv/c^2) = (?+?)(1+??/c^2)

Edited by TonyYuan2020
##### Share on other sites

u=0.9C or -0.9C or others?

v=0.9C or -0.9C or others?

w = (u+v)/(1+uv/c^2) = (?+?)(1+??/c^2)

u = .9C

v = .9C

Vx = .9C

Vy = .9C

##### Share on other sites

u = .9C

v = .9C

Vx = .9C

Vy = .9C

Thus w( the relative velocity between ship A and B as measured by either ship) is

(0.9c+0.9c)/(1+ 0.9c(0.9c)/c^2) = ~0.9945c = 0.994475138121547C

##### Share on other sites

Thus w( the relative velocity between ship A and B as measured by either ship) is

(0.9c+0.9c)/(1+ 0.9c(0.9c)/c^2) = ~0.9945c = 0.994475138121547C

It was a typo, it was .994, i just rounded incorrectly.

##### Share on other sites
Posted (edited)

It was a typo, it was .994, i just rounded incorrectly.

First scene:

<--A----------------------------------Earth---------------------------------------B--->

-0.9C............................................................................................................0.9C

Second scene:

Earth---------------------------------------A--->

----------------------------------------------B--->

.............................................................0.9C

Third scene:

Earth---------------------------------------A--->

.|....................................................0.9C

.|

.|

.|

.|

\/ B 0.9C

Fourth scene:

Earth---------------------------------------A--->

.。|....................................................0.9C

.。。|

.。。。|

.。。。。|

.。。。。。|

..................._/   B 0.9C    The angle is 45 degrees

Edited by TonyYuan2020
##### Share on other sites
Posted (edited)

First scene:

<--A----------------------------------Earth---------------------------------------B--->

-0.9C............................................................................................................0.9C

Second scene:

Earth---------------------------------------A--->

----------------------------------------------B--->

.............................................................0.9C

Third scene:

Earth---------------------------------------A--->

.|....................................................0.9C

.|

.|

.|

.|

\/ B 0.9C

Fourth scene:

Earth---------------------------------------A--->

.。|....................................................0.9C

.。。|

.。。。|

.。。。。|

.。。。。。|

..................._/   B 0.9C    The angle is 45 degrees

You aren't going to get different answers the more complex you make it, special relativity is correct. I don't feel like doing that situation as it would require doing alot of alegbra to find the velocities between those object as you would have to take in account alot of trigonometry, but something like this

γf = (γax - γbx(component))2γby(component)2

Edited by VictorMedvil
##### Share on other sites

You aren't going to get different answers the more complex you make it, special relativity is correct. I don't feel like doing that situation as it would require doing alot of alegbra to find the velocities between those object as you would have to take in account alot of trigonometry.

Third scene:

Earth---------------------------------------A--->

.|....................................................0.9C

.|

.|

.|

.|

\/ B 0.9C

But According to special relativity, the answer should be u=21/2/2 * 0.9c, v=21/2​/2 * 0.9c, the last answer is 0.906C.

##### Share on other sites
Posted (edited)

Third scene:

Earth---------------------------------------A--->

.|....................................................0.9C

.|

.|

.|

.|

\/ B 0.9C

But According to special relativity, the answer should be u=21/2/2 * 0.9c, v=21/2​/2 * 0.9c, the last answer is 0.906C.

Like I have said many times Newtonian physics is wrong, learn to stop using it, those aren't velocities they are Gammas γ.

Edited by VictorMedvil
##### Share on other sites

Like I have said many times Newtonian physics is wrong, learn to stop using it, those aren't velocities they are Gammas γ.

According to this theory, A and B go far away from each other. With A as the reference, B's time goes slower, and with B as the reference, A's time goes slower. We'll never know who's slower. When they meet, please tell me whose time is slower? Crazy relativity.

## Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

×   Pasted as rich text.   Paste as plain text instead

Only 75 emoji are allowed.

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.