Turtle Posted December 24, 2007 Report Share Posted December 24, 2007 Thank you Turtle!:evil:I think now I can link current with parallel analogy. At the point of seapartion of two pipes from a single pipe, the cross-section would change- I am slightly confused it would be a increase or decrease. Consequently, the amount of water flowing or current flowing would also change.Clear up to this. But here again the problem starts.:phones: When we press the pipe acting as reistors, the water pressure or P.D would increase. But P.D remains same in a parallel connection.Again , help! help! This is where the analogy starts breaking down, because electricity is not a fluid. I think in a pipe with water the resistance is found in the roughness of the pipe interior, and the rougher a pipe interior, the higher the resistance and there is actually a drop in pressure. In Ohm's law, I = V/R, if the voltage V remains constant, the current/amperage I drops with an increase in resistance R. I better stop there before I blow a fitting. :thumbs_up Hope I didn't make things clear as mud. :rolleyes: Quote Link to comment Share on other sites More sharing options...
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.