chandubaba Posted October 25, 2006 Report Share Posted October 25, 2006 1 why does more elctropositive ions gets discharged first in electrolysis.2how did faraday arrive at his laws of electrolysis3whats the relation between discharge potential and electronegativity Quote Link to comment Share on other sites More sharing options...
Jay-qu Posted October 25, 2006 Report Share Posted October 25, 2006 for every positive created a negative should also be created, charge must be conserved. This is because a positive is created when an electron leaves the atom, that electron has to go somewhere and the atom it ends up at will be negative (or in the case of an electro-chemical cell) a current flows, but an atom somewhere will take up that negative charge. Quote Link to comment Share on other sites More sharing options...
gribbon Posted February 21, 2007 Report Share Posted February 21, 2007 This is a topic which I have difficulty getting my head around (I'm about 3 years away from covering it in school), but it is my understanding that bonds between atoms with a large electronegativity difference (greater than or equal to 1.7) are usually considered to be ionic, while values between 1.7 and 0.4 are considered polar covalent. Therefore, a higher negativity means that the atom is more likely to ionize.....I think...:) What I can tell you though is that the number of electrons on the outermost shell affects ionization energy/discharge potential...If with 1,500 kJ/mol you removed one electron and required 6,000 kJ/mol to remove another electron and then 5,000 kJ/mol, etc, the element would have had one electron in its outermost shell. (Must be a metal) then... Look at this link: Ionization potential - Wikipedia, the free encyclopedia Quote Link to comment Share on other sites More sharing options...
ronthepon Posted February 21, 2007 Report Share Posted February 21, 2007 I'm not sure about this, but I think that Faraday's laws were 'discovered', not exactly derived from the beginning. They were probably formed as conclusions to experimental observations. However, we can arrive at the results quite easily. Quote Link to comment Share on other sites More sharing options...
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