Diamonds Posted January 3 Report Share Posted January 3 E = mc^2 in which c^2 is shape of an object. Real mass is M / c^2 that is 89 mrd times less than Visible mass. To count dark mass should be easy. 4.9 % visible mass 26.8 % dark mass 68.3 % dark energy VisibleM x realM = darkM 4.9 x 4.9/c^2 = darkM 4.9/c^2 = darkM/4.9 VisibleM^2 = darkM x c^2 VisibleM = Square root (darkM x c^2) When we divide 4.9 /c^2 answer is 5.45198 e-11 When we multiply 4.9 x 5.45198 answer is 26.8 That is dark mass percentage. Quote Link to comment Share on other sites More sharing options...

Vmedvil2 Posted January 3 Report Share Posted January 3 1 hour ago, Diamonds said: E = mc^2 in which c^2 is shape of an object. Real mass is M / c^2 that is 89 mrd times less than Visible mass. To count dark mass should be easy. 4.9 % visible mass 26.8 % dark mass 68.3 % dark energy VisibleM x realM = darkM 4.9 x 4.9/c^2 = darkM 4.9/c^2 = darkM/4.9 VisibleM^2 = darkM x c^2 VisibleM = Square root (darkM x c^2) When we divide 4.9 /c^2 answer is 5.45198 e-11 When we multiply 4.9 x 5.45198 answer is 26.8 That is dark mass percentage. This is sheer crackpottery. Quote Link to comment Share on other sites More sharing options...

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