Jump to content
Science Forums

Limit Definition,


Bitupon

Recommended Posts

I have a doubt regarding the definition of limit found in most calculus

books.

 

The definition of limit says that f(x) approaches the limit L as x

approaches c if, for every number e>0 there exists a corresponding

number d>0 such that

for all x 0<│x-c│< d => │f(x)-L│< e.

 

Can’t we replace │f(x)-L│< e with 0< │f(x)-L│< e? If not then why?

Link to comment
Share on other sites

I think, Erasmus, he means instead of specifying e>0.

 

The difference Bitupon is that logically, if you say "for every number" without specifying strictly greater than zero, the next bit would have to hold even for zero and negative epsilon values.

 

A more essential alternative is to use the definition of "open neighborhood" in topology but the disequalities give the same effect. High school calculus books use them because it is simpler, although topology gives a better overall view, once one has climbed the hill. :hihi:

Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
×
×
  • Create New...