Three Of Einstein's Mistakes

[Masterov]

I do not put into question the Michelson-Morley experiment (speed of light is constant).

I do not preach the existence of the aether.

I show that the problem that Einstein decided to have more than one solution.

 

Einstein's first mistake

 

Instead of having to make an absolute time, Einstein made absolutely for scale of diagonals. 

(\(y\) and \(z\) of Lorentz transformations).

 

We shall correct this error.

 

 

[Masterov]

Master Theory

(The first Einstein's mistake)

 

Consider the light clock with a pair of vertical mirrors:

If the distance between the mirrors \(L\), the clock's period is calculated as:

\(T=\frac{L}{c}+\frac{L}{c}=\frac{2L}{c}\)

 

--------------------------------

 

Suppose now that the observer is moving with velocity \(v\) (left and right):

Then the clock will moving like this (in our frame of reference):

 

 

\(T=\frac{L}{c+v}+\frac{L}{c-v}\ \neq\ \frac{2L}{c}\)

This situation can be resolved in three ways:

1. There was a dilation of time \(T'\) and contraction of the longitudinal scale \(L'\) (SRT);

2. There was a visual reduction of the longitudinal scale \(L'\) and the absolute time (Master Theory);

Consider the second case , which corresponds to the Master Theory:

\(T=\frac{L'}{c+v'}+\frac{L'}{c-v'}\ = \frac{2L}{c}\)

 

Then the longitudinal scale as a function of speed:

 

\(\frac{L'}{L}=1-\frac{v'^2}{c^2}\);

 

Time:

 

\(\frac{T'}{T}=1\)

 

Einstein's Formula:

 

\(\frac{L'}{L}=\sqrt{1-\frac{v^2}{c^2}}\);

 

\(\frac{T'}{T}=1/\sqrt{1-\frac{v^2}{c^2}}\)

\(v\) - the real speed of the observer, and

\(v'\) - visual speed of the clock relative to the observer.

 

 

 

\(\frac{v'}{v}=-(1-\frac{v'^2}{c^2})\)

\(v=-\frac{v'}{1-v'^2/c^2}\) - This formula allows us to calculate the actual speed of the remote relativistic object (galaxy), if it is possible to measure its visual speed.

\(v'=-\frac{2v}{\sqrt{1+4v^2/c^2}+1}\)

\(\frac{L'}{L}=\frac{2}{\sqrt{1+4v^2/c^2}+1}\)

The real speed of the observer can be calculated by integrating the acceleration:\(v(t) = v_o+\int_o^ta(t)dt\)

 

Acceleration is absolute, and can be measured by a mass and a spring.

\(x=vt\)

\(x'=v't\)

 

 

[Masterov]

Let us discuss the relativistic effects of transverse movement

Consider the light clock with a pair of horizontal mirrors (top and bottom):

Then: \(T=\frac{2H}{c}\)

Suppose now that the observer is moving with velocity \(v\) (left and right):

 

 

The trajectory of the photon will be the sawtooth:

Photon will have to travel long distances in the same time. But the photon can not travel faster than the speed of light, so here we can enter the time dilation (as did Einstein) or we can enter a reduced distance (\(H'\)) between the mirrors (Master Theory):

 

\(\frac{H'}{H}=\sqrt{1-\frac{v'^2}{c^2}}\)

 

\(\frac{H'}{H}=\sqrt{\frac{2}{\sqrt{1+4v^2/c^2}+1}}\)

 

SUMMARY: It will be correct as follows:

 

\(\frac{L'}{L}=1-\frac{v'^2}{c^2}\)

 

\(\frac{T'}{T}=1\)

 

\(\frac{H'}{H}=\sqrt{1-\frac{v'^2}{c^2}}\)

 

 

But Einstein did so:

 

\(\frac{L'}{L}=\sqrt{1-\frac{v^2}{c^2}}\)

 

\(\frac{T'}{T}=\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\)

 

\(\frac{H'}{H}=1\)

 

(It is a mistake.)

 

Let's fix the Lorentz Transformations

The visual coordinates and visual time: (marked with an apostrophe):

\(x = -\frac{x'+v't'}{1-v'^2/c^2}\)

\(y = \frac{y'}{\sqrt{1-v'^2/c^2}}\)

\(z = \frac{z'}{\sqrt{1-v'^2/c^2}}\)

\(t = t'-\frac{v'x'}{c^2}\)

 

Edited April 27, 2016 by Masterov

[Masterov]

Einstein's second mistake

Relativistic effects are part of the Doppler effect.

Doppler effects in EMW different from what we observe in acoustics

 

Einstein declared relativistic (visual!) effects - real effects.

 

I will explain:

 

To us to mind do not come to claim that:

if a person is removed, its growth is reduced.

We understand that we observe the visual effect.

Changing the size of relativistic objects are a visual effect.

 

 

Lorentz transformations (even if it had not lied)<BR>describe the visual coordinates and time.

 

A actual position and a actual speed

can be obtained by

integrating the acceleration.

 

The acceleration is the absolute,

and it can be measured by the mass on the spring.

The actual position and speed:

\(\vec v(t) = \vec v_o+\int_o^t\vec a(t)dt\)

\(\vec r(t) = \vec r_o+\int_o^t\vec v(t)dt\)

Edited April 27, 2016 by Masterov

[Masterov]

Not only time, but the mass is absolute too.

 

Einstein's third mistake

Edited April 27, 2016 by Masterov

[sanctus]

So why can we measure say muons? They decay very quickly in proper time, but thanks to time dilatation we can measure them when they move at relativistic speeds...

[Masterov]

So why can we measure say muons? They decay very quickly in proper time, but thanks to time dilatation we can measure them when they move at relativistic speeds...

Are  you remeasured the speed of muons?

 

I think that you did not do it.

 

Einstein suggested that nothing can travel faster than light, and you took this suggestion as a proven fact.

 

You have measured the length and divided it into the speed of light. So you've got the time.

 

Is not it?

Edited April 27, 2016 by Masterov

[sanctus]

As far as I understood you say there is no time-dilatation, right?

If that is rightly understood then  it follows that we should never detect a muon since its half-life in its proper time would be its halflife in all reference frames and hence we could never detect it because it decays too quick. (Or maybe not never detect it, but much less since its half life is 2.2 \mu s).

And no I did not do anything you say, I just took the muon in its restframe and then interpolated from you saying there is no time-dilatation.

[Masterov]

Two options:

 

1. It was time dilation (dilatation).

 

2. The muon moving faster than light.

 

Is it clear now?

[Masterov]

Relativistic effects are visual effects, and are part of the Doppler effect.

[Masterov]

Visual speed is related to the actual speed as follows:

 

\(v'=-\frac{2v}{\sqrt{1+4v^2/c^2}+1}\)

 

The force exerted on the electric charge in the electromagnetic field:

 

\(\vec F=q(\vec E-[\vec r\vec {rot E}]+[\vec v\vec H])(1-v^2/c^2)\)

 

If the actual speed (with respect to the field source) of matter becomes equal to the speed of light, then its is no longer interact with the field. This matter becomes a neutrino and dark matter becomes.

 

Visual speed can not exceed:

 

\(v'=\frac{2c}{\sqrt{5}+1}=185281928,6\ m/c\)

 

We can not see a galaxy, which would move faster.

Edited April 28, 2016 by Masterov