HamChem Posted April 15, 2008 Report Share Posted April 15, 2008 Could someone help me with this AP Chem type question on how to solve it... "A steady electric current is passed through molten MgCl2 for exactly 1.00 hour producing 243 g of Mg metal. If the same current is passed through molten AlCl3, for 1.00 hour, the mass of Al metal produced is closest to... a.) 27.0gb.) 54.0gc.) 120.gd.) 180.ge.) 270.g Help me out if you can!! Quote Link to comment Share on other sites More sharing options...
UncleAl Posted April 15, 2008 Report Share Posted April 15, 2008 Write the equation for reduction of Mg(II) to Mg(0). Given mass of product, how many moles of electrons went in? If you do the same things for aluminum, how may moles of Al(0) come out? Convert to grams. Quote Link to comment Share on other sites More sharing options...
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