Geocentric Posted January 26, 2007 Report Share Posted January 26, 2007 1) The curie temperature of iron is 1043 Kelvin. Assume that iron atoms, when in metallic form have moments of 2 Bohr magneton per atom. Iron is body centered cube with lattice parameter a = 0.286 nm. Calculate the curie constant.I solved it in the following way: Let m be the magnetic moment of an iron atom, let N be the number of atoms per unit volume, let K be the boltzmann constant, let mu be the permeability of free space and let C be the Curie constant.m = 2[m(:D] {where m(B) is Bohr magneton} = 18.54 x 10^(-24) A-m^2N = n/(a^3) {where n is number of atoms in 1 cubic lattice of iron} = 2/[(0.286 x 10^(-9))^3] = 8.5 x 10^28 atoms per unit volume C = [(m^2)(mu)N]/[3K] C = 0.89But the answer given in my book is 0.66. Someone good in solid state physics please help me! Quote Link to comment Share on other sites More sharing options...

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