Voxel theory of universe

[Jv1]

All data used in this theory can be found in encyclopedia Brittanica on line.

 

A voxel grid — or stack of cubes — has one red voxel inside.

 

 

 

 

The vibration movement of the planes will be used to move this voxel through the tightly packed voxels.

The planes’ center is the red cube.

 

The planes are going to move in sequence similar to this.

 

 

However, the movement will take place one voxel distance at a time and the movement’s pattern is that of the red voxel.

I call it a zig-zag helix.

From the left,

the blue vertical line in the direction of Y for a distance of one voxel;

Then the red line in the direction of X, followed by

the blue line in direction of Z.

 

 

 

The zig-zag helix is created by the red and blue lines.

 

To move the red voxel in a circular pattern, aloop,

 

the vibration sequence of the planes will besynchronized.

However, in 3D, the zig-zag helix loop would look like this

and part of the zig-zag helix loop would move like this.

 

 

In a tightly stacked voxel (cubes), to move one cube the distance of one voxel at a time,the hole plane or column in the hole voxel grid must be moved the same distance .

Vibrations of single columns of the voxel grid would look like this:

 

 

 

Loops can move in a CW or CCW rotation throughout the vowel grid.

In addition to this circular motion, there is a 

SPIN motion (blue/red lines), which can move in the direction of CW and CCW, too.

Let’s call this zig-zag helix loops  WAVES .

 

The points where the zig-zag helix loops interlock—(D)one spinning CW and the other CCW—

 

 

 

would create spinners (green, red, and blue).If three zig-zag helix loops were interlocked,the interlocking points would look like this:

 

Let’s call these  interlocking points PARTICLES.

 

 

In the real world, let’s try to put the voxel grid in the solar system with 000 point at the center of the Sun.

 

The size of the voxel cube will be a Plancklength of 1.6x10w-35m.The Planck length is the smallest calculated vibration in the universe.

 

 

 

 

 

 

The energy emitted from 1 m2 of the Sun’ssurface:

 

That is, 6.2x10e7 w/m2.

The energy reaching the Earth is

1370w/m2.

 

The inverse square law is a well-known fact—why I am I pointing this out?

 

Hypothetically—Let’s try to see the energy emitted from the Sun as a mass.

The energy converted to a mass on the surface (top of atmosphere) of the Earth will be 

1370=Me x 9x10e18.

 

Me=1.5x10e-16kg

 

The mass of energy on the surface of the Sunwould be

 

Ms=6.8x10e-11kg.

 

 

Then, we are going to follow the mass flow rate law:

 

The energy/mass emitted from the Sun

goes from the center of the Sun and makes atriangular shape.

 

 

The long red line is the size of Earth’s radiusof 6.3x10e6m.

Using the Earth–Sun distance (1.51x10e11)and the radius of the Sun (6.96x10e8),

we can calculate the length of the small red line on the Sun.

The length is

L=1.45x10e4 m.

 

That is a very small area of surface of the Sun, isn’t it? It emits energy to cover the Earth’s surface.

If the mass flow rate formula (from) above is applied, we can calculate that the density of the Sun energy/mass

is 5.6x10e-21kg/m3 on the surface 

of the Earth.

m=r v a 

The area of Earth used for this (big red line ).

 

IF THE MASS FLOW RATE FORMULA IS USED AGAIN—this time on the surface of the Sun—

The area used has the diameter OF THESMALL RED LINE.

THE density is the same.

 

This is the first interesting fact. We measured that the Sun’s energy follows the inverse square law because waves are spreading increasingly apart the further away from the Sun they travel.

 

 

BUT IF THE ENERGY IS SEEN AS A MASS, the mass flow rate is constant throughout the universe and the only difference is in the AREA for which we are measuring the mass flow rate—everything else is constant. THIS MAKES MORE SENSE, right?

 

HERE COMES THE SECOND and THE MOST-IMPORTANT PART:

 

The density of mass (converted  from energy)is 5.1x10e-21kg/m3.

That is very close to the density of dark matter in the solar system.

 

Let’s describe the movement of mass (converted from Sun energy) as the movement of PLANCK-SIZED VOXELS.

 

The electromagnetic waves are loops of Planck voxel zig-zag helix loops that travel at the SPEED OF LIGHT.

Atoms are points where loops

intersect and VIBRATE.

 

The space in between is dark matter—THE NONMOVING PLANCK VOXELS.

 

Third part of the email:

 

To connect voxel loops, points of interlocking and static loops, let’s use the BERNOULLI PRINCIPLE.

 

A ball flying through the air and spinning has a very interesting effect.

It creates different pressure on opposite sides of the ball.

 

If two objects are moving through fluid, they create zones of different pressure.

 

Let’s take a closer look at the pressures created by a couple of objects (in this case acar and a truck).

 

If instead of a car and truck we use 

two spinning balls,

 

we can see the pressure zones between the balls (the balls are spinning in the same direction):

On the left side of the big ball,

Po will be HIGH pressure, and on the opposite side, in between the balls, the right side of the big ball will have a small pressure zone.

This zone will act on the left side of the small ball with HIGH pressure.

On the right side of the small ball, the pressure will be SMALL.

 

THE DIFFERENT PRESSURES IN BETWEEN THE BALLS WILL ALWAYS KEEP THE BALANCE OF OUTSIDE PRESSURES AT AN EQUILIBRIUM.

 

Fourth part of the e-mail:

 

The Earth and Sun are traveling through space at a speed of 2.3x10e5 m/s.

Let’s calculate the pressure acting in between the Earth and the Sun if the density of the medium they are moving inside (Planck’svoxel grid is 

5.1c10e-21kg……)

The same can be calculated for a proton and neutron in a deuterium nucleus traveling at the same speed. Plus, we know the exact force of separation—10e4N….

 

The flow of PLANCK’s voxel in between spheres (or sphere-like objects) THAT ARE SPINNING

will create an attraction/repelling equilibrium pressure system (Po, Pi).

THE FORCES CREATED BY THIS PRESSURE SYSTEM will create ALL FORCES IN NATURE,

 

INCLUDING GRAVITY.

 

 

The strength and direction of force will depend on the equilibrium system (Po, Pi)values, the distance between the spheres and the direction of spin of the spheres .

 

[Jv1]

Red voxel inside video grid

 

[Jv1]

One more view of red voxel inside the voxel grid

 

[Jv1]

Zig zag helix loops created  by the vibration movement of voxels

 

[Jv1]

zig zag helix loops can have different diameter and thickness - depending how many voxel cubes are involved.
 

Zig zag helix loops are mirror images.

and when the interlock ,in the area  where loops are of touching they create chiral 

connection .

 

that point  could be seen as a particle

 

the test of voxels moving in the rest of the loop can be seen as wave- or electro magnetic field- hypothetically .

 

 

[Jv1]

The sun emits 10e26w per second.

if sun is seen as a knot- place where many zig zag loops interlock- the voxels coming out sun are seen as waves.

They travel from the Center of sun outwards.

Calculating the mass of voxels  emitted from sun in one second can be calculated.

The mass flow rate on the surface of sun(small red line on sun) will be equal to

mass flow rate on the big red line anywhere in solar system.

If the big red line is area of earth 

calculating mass emitted by suns small area 

will be equal to mass received by earth 

(big red line).

If the density of voxel cubes is 1.2x10e-26 kg/m3

density of dark matter in solar system 

the energy calculated from mass flow

will be equal to energy emited by the swim and revived by earth.

 

 

[Jv1]

Closer look at mass flow rate formula .

m=r x v x A

m- mass flow rate

r- density 

v- speed 

A - area
 

The mass flow  of voxels emitted from sun rate follows inverse square law.

Hete is the reason why:

The same amount of mass (number of voxels coming out of sun)coming through the smaller area at the same time will “Spread thin” at the bigger area (area of earth)on the distance for the same period of time.

The electromagnetic and gravitational energy follows inverse square law -why?

 

According to voxel universe theory:

The voxel(cube size of Planck) can be seen as point particle 

The mass of this particle (if density of dark matter is applied) is 4.3x10e-126kg- we can say it is massless particle.

Flow of these particles (Planck voxel cubes)at speed of light is energy 

And inverse square law nature of electromagnetic and gravitational energy 

can be explained by mass flow rate.

 

Now connection between dark and baryonic matter can be established by

Bernoulli principle if the voxel cubes create fluid we call dark matter.

 

 

 

 

 

 

 

 

 

[Jv1]

If the universe is made of 0 particles - Plancks size cubes- some people call it Graviton- the universe  hypothetically can be described as a super fluid.

The bernouli principle applies.

Here is about 10min read of very interesting findings:

A graph of a strong nuclear force
 coincidentally looks like a diagram of cavitation for pumps.
 

 If fluid passes between two spheres, it follows the Bernoulli principle.
The single sphere moving though the fluid creates a bubble with pressure zones around the sphere.
 
 
The fluid travel  between spheres will create attraction force—suction between spheres, and the sphere with the bigger mass will attract the smaller sphere toward itself.

For example, from the diagram of the strong force, we can see that the proton and neutron (1.08 mass/size of proton )
attract each other with a force of
20000N.
Let’s hypothetically put this pair of spheres in dark matter (we hypothetically assume that dark matter is fluid).
The speed of movement will be V1=600km/s, which is the speed of the Milky Way through space.

 The pressure of outer space is P1=1.3x10e-11Pa.
From the diagram of the strong force, we can see that the distance of 1 fm of the strong force is the strongest.
At a distance of 2.7fm, the strong force is equal to 0N.
The bubble of each sphere (proton/neutron) creates a single bubble.
similar to the bubble above .
The area of the combined bubbles (Figure 😎 is area A1.
The area A2=A1-Ap- An
 
 where Ap is the area of the proton, and An is the area of the neutron.
From formula
A1xV1=A2xV2,
we can calculate the V2=7.46x10e5.
From Bernoulli’s formula, we can calculate P2=-(minus-suction) 5.24x10e-11.
P diference is=P1- P2=[1.6-(-5.4)]x10e-11.
P difference=6.54x10e-11
The force F- attraction force - suction created. F=Pdifference x Ac

 where Ac is the area of contact between bubbles.
Ac=F/P difference
Ac=2.5x10e4 /6.54x10e-11
Ac=0.38x10e15me2
That is a huge area of contact for bubbles with diameters of 10e-15m.
What if the height of the bubble in the north– south direction is actually big?
What if two bubbles created by a proton and neutron moving in a low-density fluid like dark matter have a spindle-shaped area of interaction?.
Let’s try to calculate height H of the bubble.

 H=A/C
The circumference of the proton–neutron bubble (shape 8 from above)
H=0.38x10e15 / 3.6x10e-15 H=1x10e28m
This is very unusual; the estimated size of the universe is 10e26m?
If the same calculation is repeated for
van der Waals forces (using the graph) and molecular forces, the height of each bubble contact is approximately 10e28.
For the Sun and the Earth—if the same formula is applied and the C (circumference) of the bubble is the circumference of the circle from the center of the Earth to the Sun + the circumference of Circe from the center of the Sun to Earth(10e8m).
The height H of the Earth–Sun bubble is 10e32m.

 

  

At 0.5x10e26 in the direction north from the proton–neutron pair—the pressure is 0N.
Following the graph above, the force is 20000N between the proton and neutron.

 And it goes back to 0 at 0.5 x10e26m from the proton–neutron pair in the direction south.
If the universe has a Fractal nature, there has to be the smallest bubble.
What would the smallest bubble be in nature? It would be the bubble created by two of the smallest particles in universe.
To calculate the smallest bubble, we have a few clues.
The first clue is the speed of light.
3x10e8 m=V2
The second clue is that H height of the bubble is 10e26m.
The P1=1.3x10e-11, and the speed V1=600km/s
Additionally, we are going to use

 Planck‘s mass M=2.1x10e-8kg.
This is the smallest mass that has properties to create gravitation.
Planck’s constant is
h=6.6x10e-34.
This is the smallest photon traveling at the speed of light.
Let’s show in 2D what the smallest bubble looks like.
I
() (oo) ()
I
The smallest bubble:

 I ()
() [(oo)(oo)] ()
()
I
Next, a bigger bubble created by the two smallest bubbles:
.......
[(Sun)(Earth)]
Bubble
(o o)
Top view of the smallest bubble:
I

 ()
()
(o o) (o o) (o o) (o o)
() ()
I
The Planck’s mass bubble created by
N number of smallest bubble pairs.
The height of the bubble pair stack is 3x10e8 m (distance traveled inside the bubble with a diameter of a single smallest bubble, but with N number of particle pairs to reach Planck’s mass).
N=3x10e8 / r N=Mp - Mpc

 The mass of the smallest bubble is calculated from Planck’s constant.
Form
E=h x f
F=1(1 turn on 3x10e8m) E=6.6x10e-34
Mpc=7.7c10e-24/3x10e8=0.73x10e-50kg N=Mp /Mpc=2.1x10e-8 / 0.73x10r-50
N=2.8x10e42 number of pairs in the single elongated bubble.
The thickness of the smallest bubble inside the stack of the 2 smallest particle stacks is equal to the height of the bubble.
They are all using a single tensor 10e28 long to travel together and create Planck’s mass.
The diameter of the bubble will be r=3.8x10e8 / 2.8x10e42

 r=1.07x10e-36m
From this diameter, the area of the smallest bubble A1 is calculated.
A1=1x10e-72me2
A1 x V1=A2 x V2
A2=1x10e-72 x 6x10e5 / 3x10e8
A2=3x10e-75
A2=2 Asp
where Asp is the area of the smallest particle.
1.5x10r-75=Asp=15x10e-74
Rsp=1.73x10e-38m******
where Rsp is the radius of the smallest particle.
THE PLANCK LENGTH IS
1.6x10e-35 ********

 
IF DARK MATTER IS FLUID, IT WILL CREATE A RESISTANCE-DRAG FORCE. THE FORMULA FOR THE DRAG FORCE:

   FROM THE DRAG FORCE, THE ENERGY LOST TO FRICTION IS CALCULATED. FOR A SINGLE PROTON ,USING THE SAME CONDITIONS AS ABOVE (speed), THE COEFFICIENT OF FRICTION IS:
Coefic of friction=Et/Eloss Et=m v2

 Eloss=Fdrag x distance
The COEFFICIENT OF FRICTION FOR DARK MATTER—calculated for a proton, the Earth and the Sun, comes to be
1.67x10e-19 value.
HERE IS THE COINCIDENCE THAT IS HARD TO IGNORE.
THE ENERGY LOSS OF THE EARTH IS Eloss=14.6x10e15J**********
THE LOSSES CREATED BY DRAG FORCE HAVE TO BE COMPENSATED
FOR THE EARTH NOT TO LOSE THE MOMENTUM GIVEN TO IT BY THE BIG BANG.
THE MECHANISM TO ACCOMPLISH THAT TASK IN THE CASE OF THE EARTH IS:

 THE EARTH RECEIVES ENERGY FROM THE SUN IN HEAT AND LIGHT AND ABOUT 10% IN UV ENERGY.
THE SAME AMOUNT OF ENERGY IS RELEASED MOSTLY BY DEFLECTION AND IR RADIATION.
UV-C (ultraviolet) RAYS CARRY 10 TIMES MORE ENERGY THAN IR (infrared) RAYS.
9/10 OF ENERGY CREATED BY UV-C RAYS COMING FROM THE SUN IS Euvc=69.8x10e15J**********
THAT IS ONLY 4 TIMES LESS THAN THE ENERGY LOSS OF THE EARTH TO DRAG. *******
THE UV RAYS CREATE A SWELLING OF THE IONOSPHERE BY ACCELERATING ELECTRONS TO THE POINT OF CREATING IONS.

 THE FASTER SPEED OF ELECTRONS WILL CAUSE A SLOWER FLOW OF
DARK MATTER INSIDE THE EARTH‘S BUBBLE ON THE SIDE FACING THE SUN. THE DIFFERENCE IN PRESSURE WILL CAUSE THE FORCE OF SUCTION BETWEEN THE EARTH AND SUN.
THE AREA OF THE IONOSPHERE WILL BE THE THICKEST ON THE SUNNY SIDE(12 o’clock position) AND THE IONOSPHERE IS THINNEST ON THE DARK SIDE OF THE EARTH (6 o’clock).
THIS DIFFERENCE WILL PRODUCE ENOUGH FORCE TO PUSH THE EARTH AT A SPEED OF 30 km/s ON THE ORBIT OF THE SUN.
THERE IS NO PRESSURE DIFFERENCE AT (9 and 3 o’clock) ON THE EARTH—DUSK AND DAWN—BUT THE DIRECTION OF THE FORCE WILL BE THE OPPOSITE, CREATING A 24-hour ROTATION OF THE EARTH.
ALL THE UV-C RAYS STAY IN THIS LAYER.
    
 IF THE DARK MATTER IS FLUID, THE EARTH BUBBLE WOULD HAVE
BLUE PRESSURE LINES IN THE NORTH– SOUTH DIRECTION.
PERPENDICULAR LINES WOULD BE LOW- PRESSURE ZONES (red in the diagram above).
THIS WOULD EXPLAIN WHY THE SUN AND THE PLANETS TRAVEL AT THE SAME SPEED; THE PRESSURE INSIDE THE BLUE ZONE IS THE SAME FOR ALL PLANETARY BUBBLES INCLUDING THE SUNS.
THE PRESSURE IN THE RED ZONES IS THE SAME, WHICH IS ACCOMPLISHED BY DIFFERENT DISTANCES BETWEN THE SUN AND THE PLANETS.

 Are all these calculations above just coincidences?
What is your opinion?
If this is not a coincidence, here are a couple of very interesting things that can be explained in astrophysics:
Mercury’s perihelion shift-speeding:
Mercury at perihelion would create increased suction between the Sun and Mercury bubble and the force of the suction would lift chunks of the Sun’s surface plasma, creating SUN SPOTS.
This would cause a shift in Mercury’s trajectory.
Every planet’s elliptical trajectory is created this way, but the angle of the shift is so minuscule that we have not been able to detect it.
Another interesting thing is that the Sun spot cycle galosh’s every 11 years .

 Jupiter’s perihelion happens every 11 years. Additionally, the superposition synergy of bubbles created by other planets would create enormous SUN SPOTS—depending on the position of planets in their orbits. There were attempts to connect the position of planets with Sun spots, but the mechanism of the link was never found.
This could be it.
Second—if the Planck constant is really the smallest mass of dark matter,
that would explain why gravity interacts with the light flow of different masses if dark matter would create different suctions and the light would bend in the gravitational field.
Next—all forces would be unified. They are all suction created by the Bernoulli principle of Byron particles moving inside the dark matter.
Newtonian physics is enough to explain the Sun’s atomic particle interaction .

 Then, if the Milky Way is seen as a single bubble moving through the dark matter, the blue pressure zone (from the diagram above) would “flatten” the galaxy to its present shape.

 

[Moontanman]

This thread is closed due to complete lack of rigor in explaining how this works and why it is true.