Jump to content
Science Forums

Organic Chemistry Problem- percent yield?


Recommended Posts

  • 3 months later...

Please note that I have had to make a few asumptions about this question. Firstly that the reaction was infact a DEhydration reaction and that water was removed. Also I have had to assu0me that the only product of the reaction was 2-methyl 2-butene and its isomer 2-methyl 1-butene was not created. Using that as a basis, I used the amounts provided to calculate the Moles of the compounds used. Knowing the substance in shortest supply is the limiting reagent in this question, the 2-methyl 2-butanol was taken as the limiting reagent at a concentration of 0.011moles (assuming the chemicals used were pure). Since the dehydration reaction from butanol to butene (shortening the name for handiness) is a 1:1 reaction the amount of then 0.011 moles of the 2-methyl 2-butene should have been created and that should be an amount of 0.77143g should be created. To calculate the percentage yield divde the amount created by the expected yield and multiply it by 100%. So, 0.386g/0.77143g *100 = 50.03%

 

So the answer to your question is that the yield in this reaction is approximatley 50%.

Link to post
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
×
×
  • Create New...