sciencegirl07 Posted June 1, 2008 Report Share Posted June 1, 2008 This is probably much easier than I think, but I need to calculate wavelength using velocity. What is the formula for that? Thanks! Quote Link to comment Share on other sites More sharing options...
sciencegirl07 Posted June 1, 2008 Author Report Share Posted June 1, 2008 ok never mind, just figured it out, thanks anyway! Quote Link to comment Share on other sites More sharing options...
modest Posted June 1, 2008 Report Share Posted June 1, 2008 Good link: Wave nature of electron and DeBroglie wavelengths at hyperphysics.phy wavelength = h/(mass x velocity) If you have a specific problem that you have tried to work out - please post it. -modest Quote Link to comment Share on other sites More sharing options...
sciencegirl07 Posted June 2, 2008 Author Report Share Posted June 2, 2008 The question I'm currently having trouble with is:The work function for lithium is 279.7 kj/mol. What is the maximum wavelength of light that can remove one electron from one atom of lithium metal? and...The ionization energy of gold is 890.1 kj/mol. Is light with a wavelength of 225nm capable of ionizing a gold atom? I'm yet to wrap my head around this material, clearly. Any help would be appreciated! Quote Link to comment Share on other sites More sharing options...
ronthepon Posted June 2, 2008 Report Share Posted June 2, 2008 This is probably much easier than I think, but I need to calculate wavelength using velocity. What is the formula for that? Thanks!Wavelength using valocity of what? An electron? If so, the kinetic energy will probably have to be equated with photon energy. Maybe you'll have to add the work function to the KE of the electron. Quote Link to comment Share on other sites More sharing options...
modest Posted June 2, 2008 Report Share Posted June 2, 2008 The question I'm currently having trouble with is:The work function for lithium is 279.7 kj/mol. What is the maximum wavelength of light that can remove one electron from one atom of lithium metal? First convert your work function to electron volts. You can do this easy enough knowing one eV equals 96.485 kJ/mol. Then you can use this equation:[math]\lambda = \frac{hc}{\phi}[/math]where [imath]\lambda[/imath] is the wavelength (what you're looking for)c is the speed of light (use 2.9979 x 10^17 nanometers/second to get your answer in nanometers)h is plank's constant (4.13566 X 10^-15 eV/second)and [imath]\phi[/imath] is the work function in electron Volts - what we are given That will give you the largest wavelength that can eject an electron from a lithium plate. You can both check your results and get a good description of the photoelectric effect here. By check your results, I mean you can input eV toward the bottom of the page and get a wavelength. and...The ionization energy of gold is 890.1 kj/mol. Is light with a wavelength of 225nm capable of ionizing a gold atom? You can use the same formula as above. Instead of "work function" being the energy in eV or [imath]\phi[/imath], it is "ionization energy" - but the equation is the same. See if the resulting wavelength is larger or smaller than 225 nm. -modest Quote Link to comment Share on other sites More sharing options...
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