bluesky Posted April 11, 2007 Report Share Posted April 11, 2007 Consider a gravity free hall in which a tray of mass M,carrying a cubical ice block of mass m and edge L,is at rest in the middle.If the ice melts,what would be the displacement of the system? I think it has to do with the conservation of momentum,since no external force is acting.But i cannot think further.Please help. Quote Link to comment Share on other sites More sharing options...
bluesky Posted April 11, 2007 Author Report Share Posted April 11, 2007 I think I have got the answer.F=M(d^2R_cm/dt^2)=dP/dt=oTo have even a uniform motion of CM,what we need is a motion of CM from the rest.That must involve an acceleration.Since acceleration of CM is zero,we must conclude that CM did not move at all.Please check if I am correct. Quote Link to comment Share on other sites More sharing options...
ronthepon Posted April 11, 2007 Report Share Posted April 11, 2007 Yes, the displacement of all the particles (the center of mass of the system will be zero. Quote Link to comment Share on other sites More sharing options...
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