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Help solving equation


94c4lt1

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From ImZ's work, I see how I was off by a factor of 10. At least from an Astronomer's point

of view this puts me in the ball park (w/i factor of 10).

 

Maddog

 

ps: 94c4lt1: ImZ's calculation is the correct one. You do need to account for .15 => 1.5e-1 in

addition to cm => 10 mm and then squaring. That would give 2083 sec.

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sorry, i almost forgot this topic...

 

ok, lets do the calculation all over again:

.15 (ws/mm^2)

notice its 1/mm^2, not mm^2

so, (.15 ws/mm^2) * (1 mm^2/ 10^ -6 m^2) = .15 * 10^6 ws/m^2 = 150000

720 uW/cm^2 (*its 1 over cm^2) * (1cm^2 / 10^ -4 m^2) = 720 *10^4 uw/cm^2

(720 *10^4 uw/m^2) * (1 W/ 10^6 uW) = 720 * 10^ -2 = 7.2

150000/7.2 = 20833.333~

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