Nootropic Posted February 18, 2007 Report Share Posted February 18, 2007 I know that boiling points of solutions containing volatiles solutes are actually depressed, but would this imply that the freezing point of a solution (say, oh, containing methanol or ethanol) with a volatile solute would be elevated? I can't seem to find anything to guarantee my thinking. Anybody? Quote Link to comment Share on other sites More sharing options...
ronthepon Posted February 18, 2007 Report Share Posted February 18, 2007 If you're adding Volatile chemical #2 to V.C.#1, then the resulting solution may have a higher vapour pressure. That will only be when pure V.C.#2 has a greater Vapour pressure than pure V.C.#1 It's as simple as that. Assuming ideality in solution formation, addition of a more volatile solute will increase the vapour pressure. Quote Link to comment Share on other sites More sharing options...
Nootropic Posted February 18, 2007 Author Report Share Posted February 18, 2007 I know the vapor pressure of the solution will increase, which in turn causes a decrease in boiling point ("boiling point depression") but I'm not sure if the increase in vapor pressure also causes an increase in the freezing/melting point of the solution ("freezing point elevation"). The solutions in question would be a water-ethanol and a water-methanol solution (water is the solvent); like I said, I know for sure that the boiling point is lower than that of pure water, but I don't know if the freezing point would be greater than that of pure water. Quote Link to comment Share on other sites More sharing options...
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