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Gravielectromagnetism - The Next Part Of The Investigation

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#1 Dubbelosix



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Posted 22 June 2019 - 10:06 AM

Following up on an interesting paper that was posted by a facebook friend, it is nice to see that the applications of gravity ultimately on a fundamental scale many postulations that I found when investigating gravity under geometric algebra - that is, that the torsion and ultimately centrifugal pseudo forces are not only seen as a correction term for quantum systems, but are inherently part of general relativity. It is in other words, inescapable to postulate a zero torsion in Einstein's equations - whereas modern physics has often neglected the term in probably the most consequential ways possible. It will always sum as a symmetric and antisymmetric part to the field equations.


In the following paper




It is seen that gravity applies linearly to electromagnetism in such a way that it applies uniquely to a contribution of the spin of particles (and where there is spin, there is torsion and other classical effects). So this will be the next investigations, because while I need to proof read over and over again what I have planned, this will be a continuing side-project so that I don't become mad on one subject alone. The following work will need to be composed into one paper as well and then I will be using the cited paper to extend the postulations that have been discovered.






As the project continues, I will be using this thread for the updates of what I find. The spin domination for gravity is the only way both these two last links can be fully appreciated.



#2 Dubbelosix



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Posted 24 June 2019 - 10:51 PM

Gravielectromagnetism and Drag Part 2


The gravimagnetic field defined for magnetic coupling to orbit is, as the master equation we will work from:


[math]\mathbf{B} = \frac{1}{mc^2 e} \frac{1}{r} \frac{\partial U}{\partial r} \mathbf{J} = \frac{1}{me}(\frac{\phi}{c^2})\frac{\partial v}{\partial t} \mathbf{J}= -\frac{1}{e}\frac{1}{Gm}\frac{\partial v}{\partial t} \mathbf{J}= -\frac{1}{me}\frac{a}{G} \mathbf{J} = -\frac{1}{me}\frac{\omega^2 r}{G} \mathbf{J} = -\frac{1}{m e} \frac{m}{r^2} \mathbf{J}[/math]


Dividing through by [math]G[/math] and using it in standard cgs units, we recover the main term [math]\frac{M}{r^2}[/math] describing gravielectromagnetism by Sciama:


[math]\frac{1}{G}\frac{P}{\rho_B} = \frac{1}{2G} (\frac{\rho}{\rho_B}) v^2\ f = g_{00}\ (\frac{\rho_A}{\rho_B}\ \frac{M}{2r^2})= \frac{a}{G} = \frac{1}{G}\Gamma_{00}[/math]


The master equation, is itself, a spin-coupling equation where we have written it in a line of equalities strongly related to gravielectromagnetism. So to get this ''spin-orbit coupling'' equation we simply use terms in the master equation derived a while back to obtain relevant terms - before we do this, we remind ourselves of the terms from the simpler equation derived:


[math]P = \frac{1}{2} \rho v^2\ f = 2 \pi \rho_A\ (\frac{ c}{ t_p}) = 2 \pi \rho_A \cdot \Gamma[/math]


We remind ourselves that [math]\frac{\rho v^2}{2}[/math] is the fluid pressure energy density from the equations of motion and that [math]\rho_A[/math] is a surface density, and so the acceleration/gravitational field is:


[math]\frac{P}{\rho_A} = \frac{1}{2} (\frac{\rho v^2}{\rho_A}) \ f = 2 \pi (\frac{ c}{ t_p}) = 2 \pi \cdot \Gamma[/math]


Dividing through by [math]G[/math] yields:


[math]\frac{1}{G}\frac{P}{\rho_A} = \frac{1}{2G} (\frac{\rho v^2}{\rho_A}) \ f = 2 \pi \frac{1}{G} (\frac{ c}{ t_p}) = 2 \pi \cdot \frac{1}{G}\Gamma[/math]


And so plugging in relevant terms from the master equation we find the gravimagnetic field dynamically related to the spin and centrifugal force:


[math]\mathbf{B} = \frac{1}{mc^2 e} \frac{1}{r} \frac{\partial U}{\partial r} \mathbf{J}  = \frac{1}{2} \frac{1}{G}\frac{1}{me} (\frac{P}{\rho_A}) \frac{\partial v}{\partial t} \mathbf{J} = \frac{1}{2} \frac{1}{G}\frac{1}{me} (\frac{\phi}{c^2}) \frac{\partial v}{\partial t} \mathbf{J} = -\frac{1}{m}\frac{a}{G} \frac{\mathbf{J}}{2e}[/math]


[math] = -\frac{1}{m} (\frac{m}{r^2}) \frac{\mathbf{J}}{2e}  = -2 \pi \cdot \frac{1}{Gm} (\frac{\mathbf{J}}{2e})\Gamma =- 2 \pi \frac{1}{Gm} (\frac{c}{ t_p}) \frac{\mathbf{J}}{2e} = -2 \pi \frac{1}{m} \cdot \omega \times (\frac{\omega \times r}{G}) \frac{\mathbf{J}}{2e} = -2 \pi \frac{1}{\mu} (\frac{\mathbf{J}}{2e}) \Gamma[/math]


With a reminder that [math]\frac{\mathbf{J}}{2e}[/math] was the Josephson constant for the magnetic flux and here, [math]\mu[/math] is the standard gravitational parameter and also with the generic gravitational field [math]\Gamma[/math] with its usual units of acceleration. Assuming the calculations have been done properly, this unites two of my theories together with that of entropic gravity.

Edited by Dubbelosix, 24 June 2019 - 10:55 PM.