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Kirol

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About Kirol

  • Birthday 02/02/1988

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  1. It's ok, I've gotten some realistic figures now. The only problem is that I don't know how I got them, exactally. I'm not sure if it's displaying the enrgy of forming or breaking the bonds. ~_~ Ah, well. Who cares when you have some results? xD
  2. Anyone?
  3. OH! Of course. I was looking for some really complicated way to do it, but this is much more simple. Thanks a load. Also, the energy released per mole is equal to 6147kJ... I think. o_O After all, the bond energies broken give a total of 2809 kJ/mol, and those formed give -3338... ΔH is products - reactants, which gives 6147 kJ... 6.147kJ / ml. Although it does seem kinda wrong. Just 1 ml giving off all that much? It can't be right... No, wait. I think I have the minuses the wrong way around, after all, it takes energy to break bonds (meaning that the reactant energy should be minus 2809kJ/mol)... lemme work this out again. Ugh. Now I get 6147 positive. If I have the products as minus, I get a massive number. If I have them as positive, I get an endothermic reaction... Methanol has 3 X C-H bonds each of which are equal to 413 kJ/mol, 1 C-O bond which is equal to 360 kJ/mol, and 1 O-H bond which is equal to 463 kJ/mol. So in total, 1 mole of methanol has 2062 kJ of energy. ½O² adds 747kJ/mol to the Reactant’s Energy. (Remember, CH³OH (l) + 1½O² (g) -> CO²(g) + 2H²O (l) ) In H²O, there are 2 H-O bonds being formed, each of which need 463 kJ/mol. So in H²O, there is 926 kJ/mol absorbed. In CO², there are 2 C=O bonds being formed, each of which need 743 kJ/mol. So in CO², there is 1486 kJ/mol being absorbed. Or am I way out, again?
  4. I was burning the methanol (ethanol, propanol, butanol, and pentanol,) in a spirit burner... the flame was heating a calorimeter with 200ml of water. The temperature of the water rose by 22 degrees, celcius. I need to find out how much energy was given out by the methanol when I burned 1.42 grams or whatever I said in my last post. From there, I can work out how much actually went into the water. And from there, I can work out the efficienct of the experiment...
  5. Ok. So I was just wondering. I've got 200ml of water that was heated up by 22°C, meaning that it'ld take 18480 Joules to get there. (cmΔT, remember.) I've got several alcohols, but let's just work with methanol right now. Methanol gives out 6147 kJ/mol of energy, right? (Including the O=O bonds used in combustion). Or am I really out there? Anyway, tell me if any of this is sounding weired to you. So, let's say that I weighed the Methanol before and after the combustion (which raised the water's (200ml) temperature by 22 degrees). The change in weight was 1.48 grams. What calculations can I use to find out how much energy the methanol used? Methanol burned = 1.48g. Water used = 200ml. Enthalpy change = 22. Thanks for your time.
  6. I have a theory. That must be a chiché around here... but yeah. I would like to know if it would work! I'm currently studying AS level biology and Chemistry... Not physics. Anyway... It's about the end ... of everything. To do this, you'll have to assume that space isn't infinate. Ok, so we all know that black holes have large amounts of gravity. So, this would mean that they are pulling each other in, as well as other things, right? Even if they have no mass, the things inside them would still have some mass, would they not? So, my theory involves black holes clashing togeather. If they cancel each other out, then my theory wouldn't work. However, if they stack togeather, their gravity would increase. Eventually, all the black holes would be in a single place, in a single massive black hole. I've heared that they effect metaphyical things, I.E. time. I'm not too sure, myself... but it should make all of time be in a single place at the end, too. Also, perhaps black holes draw in space, as well. Actual space , drawn in by black holes. Eventually, EVERYTHING would be drawn into one small ball of infinately heavy mass. Because there would then be no space for the mega-hole to exist, it will have to destroy it's self, the ball of mass would be highly un-stable and would go through several half-lives in a matter of miliseconds, and would react with the newly formed products, The mass would explode and expand, then space would once again form, the elements we now know, and everything would be stared again. Now, if time is truely absorbed by black holes, then everything would be in one time, all at the same time. This would cause everything to freeze, I would imagine. Or... something. I don't know if I've explained that very well, either... please tell me if there's anything wrong here. And don't steal if it's good! ;D Copywrited to Michael R. you hear?!
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