Thermite reaction!

[Tim_Lou]

I would suggest you to do this demonstration outside, it is too dangerous to do this indoor since molten iron will burn whatever it touches.

the energy released calculation is as following:

Fe2O3 + 2Al --> Al2O3 + 2Fe

sum of delta H of products= -1676 kJ/mol *1 mol + 0

sum of delta H of reactants= -822.2 kJ/mol * 1mol + 0

delta H for this reaction = -1676 kJ + 822.2 kJ = -853.8 kJ

so, reacting 1 mol of Fe2O3 or 2 mols of Al (comepletely) would give you 853.8 kJ.

 

I aint any chem wizard... so, calculating how high particles fly.... seems impossible to me.

 

for equipments info, take a look at this website:

http://www.ilpi.com/genchem/demo/thermite/

 

or this:

http://www.chem.umn.edu/services/lecturedemo/info/Thermite.html