JeffreysTubes8 Posted May 15, 2021 Report Share Posted May 15, 2021 (edited) The historical codex, theory of everything, cracks QM, unlike relativity and newton's laws of universal motion it's a function f(t)= Part 1; an 216 columb and 2 row [x y] coordinate matrix (sphere worlds) plus another 216 columb 2 row coordinate matrix (quantum gravity). [n n] [n n] [n n] [n n] [n n] [n n] [n n] [n n] [n n] [n n] [n n] [n n] [n n] [n n] [n n] [n n] [n n] [n n] Etc... Part 2; You take every integer in the first two matrices to the power of the product of those two matrices. Like Russian matryoshka dolls you have to do this n number times, n=radius of observable universe over the planck length. & we must root every exponent in the -z direction to superimpose the smaller and smaller x and y values in the +z direction. && everytime we do this we need to take out the top exponent from power towers and redo it for counting down to the x y coordinates of the z vector which is the center of the codex, let's call this operation V for vector. Problem with operation V, you will lose entire matrices of coordinates when you remove an exponent from the power tower, so now we must rectify that by putting op V through the power tower and plugging those values back into the base matrix, and then redoing the full power-tower with these adjusted values, but this time rooting every other iteration of exponential matrices in the power tower so that the values remain the same. Ex) Vector +3 [3.14^[√4.13^[√3.14 √4.13] [√4.13 √3.14] √3.14^[√3.14 √4.13] [√3.14 √4.13] [√4.13^[√3.14 √4.13] [√4.13 √3.14] √3.14^[√3.14 √4.13] [√3.14 √4.13]] 4.13^[√4.13^[√3.14 √4.13] [√4.13 √3.14] √3.14^[√3.14 √4.13] [√3.14 √4.13] [√4.13^[√3.14 √4.13] [√4.13 √3.14] √3.14^[√3.14 √4.13] [√3.14 √4.13]]] [3.14^[√4.13^[√3.14 √4.13] [√4.13 √3.14] √3.14^[√3.14 √4.13] [√3.14 √4.13] [√4.13^[√3.14 √4.13] [√4.13 √3.14] √3.14^[√3.14 √4.13] [√3.14 √4.13]] 4.13^[√4.13^[√3.14 √4.13] [√4.13 √3.14] √3.14^[√3.14 √4.13] [√3.14 √4.13] [√4.13^[√3.14 √4.13] [√4.13 √3.14] √3.14^[√3.14 √4.13] [√3.14 √4.13]]] & Vector -3 [3.14^[4.13^[3.14 4.13] [4.13 3.14] 3.14^[3.14 4.13] [3.14 4.13] [4.13^[3.14 4.13] [4.13 3.14] 3.14^[3.14 4.13] [3.14 4.13]] 4.13^[4.13^[3.14 4.13] [4.13 3.14] 3.14^[3.14 4.13] [3.14 4.13] [4.13^[3.14 4.13] [4.13 3.14] 3.14^[3.14 4.13] [3.14 4.13]]] [3.14^[4.13^[3.14 4.13] [4.13 3.14] 3.14^[3.14 4.13] [3.14 4.13] [4.13^[3.14 4.13] [4.13 3.14] 3.14^[3.14 4.13] [3.14 4.13]] 4.13^[4.13^[3.14 4.13] [4.13 3.14] 3.14^[3.14 4.13] [3.14 4.13] [4.13^[3.14 4.13] [4.13 3.14] 3.14^[3.14 4.13] [3.14 4.13]]] && Vector -2 part 1 [3.14^[4.13 3.14] [4.13 3.14] 4.13^[4.13 3.14] [3.14 4.13]] [3.14^[4.13 3.14] [4.13 3.14]] 4.13^[4.13 3.14] [4.13 3.14]] etc... &&& Vector -2 part 2 [36.34^[1^[1 1] [1 1] Etc...Etc.. (Note! + and negative vectors shown in example are reverse from what they should be for the Historical Codex because the values for the matrices in this example are >1 but the actual values you want will all be <1) EDIT: And there's still one final grueling layer to part 2 I'm not accounting for. Of course the original 216 coordinates of three z matrices containing 9 spheres is not I'm 3.14 4.13 it's less than one meters! So that means in the code where the -z side of the power tower are all rooted exponents, eventually it's going to yield a value greater than 1! Eventually up to 13.8/2 billion light years over one meter! So wherever that happens, every exponent above it is not going to be rooted, whatever iteration exponential matrices that is, will say the nth exponent. Part 3; Then you put your answer into a fibonacci sequence. The beginning of the sequence is 1 (first matrix) + 1 (second matrix how the gravity moves xyz up down forward back) = another matrix of sphere worlds which is multiplied by a different quantum gravity matrix which is the second iteration of this special fibonacci sequence, which is a potential universe at time equals 2 planck seconds, with 4 matrices. Etc..(note: you must know where the vectors talk to one another is equal to the generation of the gravitational matrices & when incorporating one gravitational matrix into another vector's matrices one must add or subtract it's transformational values by the difference of values between the matrices in those vectors) Ex) [n1 n1]____[n2 n2]____[n3 n3] ________+__________=_____________ [n1 n1]____[n2 n2]____[n3 n3] & [n1 n1]___[n3 n3]____[x1 y1] _______+_________=2*______ [n1 n1]___[n3 n3]____[x1 y1] && [n2 n2]___[n3 n3]__[x2 y2] ________+________=2*______ [n2 n2]___[n3 n3]__[x2 y2] &&& ___[x1 y1]____[x2 ny2]__[n4 n4] +/-_______+/-________=__________ ___[x1 y1]____[x2 y2]__[n4 n4] &&&& [n3 n3]___[n4/2 n4/2]__[nx ny]___[n5 n5] ________+_____________+________=________ [n3 n3]___[n4/2 n4/2]__[nx ny]___[n5 n5] where, nx & ny = geometric equations applied to the [n3 n3] columns' gravitational tug and [n4 n4] matrix gets divided by 2 because of the inverse square law for [n2 n2]'s gravitational tug applied to [n3 n3]'s position from when it was [n1 n1] The practical use of the codex is evolving the observable universe from the moment of the big bang to now. You will acquire a printout of all of the atoms of the periodic table, and how their quantum particles behave, with a magnification of up to 26 orders of magnitude greater than that offered by an electron microscope, and how micro lasers will effect a quantum system every planck second after your instruments perturb a system. Unlike normal quantum teleportation, which involves changes over lateral time, the codex can instead be used to teleport quantum objects using particle confusion, which is a result of analog quantum gravity, as gravity propagates in two directions, moving n-number of sphere worlds that collide to generate one higgs function to the exact quantum phonetic frequency of another higgs function, will duplicate that higgs function precisely where the other higgs function is located. This works because all potential universes are so similar at the quantum scale. Edited October 4, 2021 by JeffreysTubes8 Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted June 9, 2021 Author Report Share Posted June 9, 2021 Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted June 10, 2021 Author Report Share Posted June 10, 2021 (edited) Dark flow suggests we're presently in a level 2 multiverse on the tegmark scale, remember what I said about the short-lived dark matter universes from the previous iterations in a cyclic cosmos? Even if we were still in the first level 1 multiverse our local region of the cosmos would be the same but there would be no way dark flow could be in the cmb because that is a photograph older than the black holes that make tachyons. At least in this model. In the standard model the cmb light isn't the beginning like it is here and also black holes don't make tachyons only dark stars which is what they are in this model https://www.google.com/amp/s/www.popularmechanics.com/space/deep-space/amp35875454/what-are-black-holes-new-theory/ I did some editing to part 3, basically these p-adic matrix vectors can share gravitational matrices which need to be incorporated and their values adjusted. That about caps it off. The rest is just the geometric equations I'm hiding for finding what to put in for the matrices. Edited June 10, 2021 by JeffreysTubes8 Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted June 15, 2021 Author Report Share Posted June 15, 2021 Another way to explain https://www.quantamagazine.org/the-mystery-at-the-heart-of-physics-that-only-math-can-solve-20210610/ Similar but simpler math: https://phys.org/news/2021-06-framework-simulate-physics-hamiltonians.amp Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted June 16, 2021 Author Report Share Posted June 16, 2021 https://physicsworld.com/a/talking-quantum-dots-could-be-used-as-qubits/ Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted June 21, 2021 Author Report Share Posted June 21, 2021 To anyone trying to run their own random 324 integers through this you'd have better luck on a co-prime counterproof of Beal Conjecture. That is unless you my proofs (z)tate Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted June 21, 2021 Author Report Share Posted June 21, 2021 (edited) See for instance https://phys.org/news/2021-06-combining-classical-quantum-door-discoveries.amp What they did here was they just 🤣🤫😭😭😭😭 it's not even funny they have 3 2D vectors but each vector sequence cannot express depth it's either π & 4.13 or it's 4.13 & 22/7 so this is just 2D shyte. There's no expressions of the gravitational changes to those coordinates being implemented for a false-positive string theory esque 4D substitute Edited June 21, 2021 by JeffreysTubes8 Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted June 24, 2021 Author Report Share Posted June 24, 2021 On 5/15/2021 at 1:20 AM, JeffreysTubes8 said: Part 2; Also, don't forget to add up all of the x and y coordinates in separate matrices of the same vector; & then add all but one, then all but two, etc But they already did that judging by the image. What they didn't, and what they can't do because they don't have the geometric proof yet, was the gravitational interactions through dimension 4. Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted August 30, 2021 Author Report Share Posted August 30, 2021 On 6/9/2021 at 12:11 AM, JeffreysTubes8 said: Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted December 11, 2021 Author Report Share Posted December 11, 2021 Quote Link to comment Share on other sites More sharing options...

Autodidactocrat Posted December 15, 2021 Report Share Posted December 15, 2021 Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted December 23, 2021 Author Report Share Posted December 23, 2021 Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted May 4 Author Report Share Posted May 4 What youtuber Michael Penn (whom can’t work with triangles quite as well as I) most recently uploaded actually does refer to that complicated ‘cross-talk’ I can remedy using these matrices systems. But only I have a remedy for the 2D problem of 3 real D. Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted May 4 Author Report Share Posted May 4 (edited) Tegmark calculated there’s another Sol 10^33 meters away. As with everything LCDM model goes this calculation would be arbitrary. Much better to rule out every other possible deviation geometrically. Finally a use for a counter example to the beal conjecture where the Hubble diameter or CEH is approx = 1 Edited May 5 by JeffreysTubes8 Quote Link to comment Share on other sites More sharing options...

JeffreysTubes8 Posted May 4 Author Report Share Posted May 4 (edited) With all non-coprimes plus the primes minus 1 between identical realities in a universe that is the product of every geometric combination plus velocities of said membranes. time dilation says the dates will not be identical however there is a certain closing window in which the past becomes irretrievable. However the difference between a type 3 and infinity (alpha and omega) depends upon counting the energy requirements of an FTL to circumnavigate all the CEH points of a perfect sphere which your calculus can’t even describe due to the limit of Newton’s maths Edited May 4 by JeffreysTubes8 Quote Link to comment Share on other sites More sharing options...

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