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PDF file: 20200726WaveCurvatures.pdf

 

I have made some adjustments to the theory, as I found the strain equations in my last set of equations to not match between energy of particles and their gravitational curvature leak. I've fixed them in the equations in this pdf file. I'll write out the equations over the next few days, but they can be found in the above pdf file.

Edited by devin553344
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e^2/r is the energy for instance but you have one numerator of strain weighted by a factor of the squared strain, meaning that the dimensions cannot be justified.

A rule of thumb you do not define two quantities with the same symbol that only defines confusion and the lack of clarity will always be refuted, regardless. You cannot have the dimensions given are s

me and dubbel agree you are a crackpot, read this http://www.scienceforums.com/topic/36852-crackpottery-and-dunning-kruger-effect/

Posted (edited)

The electron mass energy from strain energy is:

 

ϵ = (hc/(εK^2e^2))^1/2

 

mc^2 = εK^2e^2/r * ϵ^2

 

Where ϵ is the logarithmic strain, h is Planck's constant, c is the speed of light, ε is the permittivity of free space, K is the electric constant, e is the elementary charge, m is the mass of the electron, r is the Compton wavelength of the electron.

 

The gravitation then is a leak of the curvature of the matter energy and relates to the electron-positron pair energy:

 

3/5 * 8Gm^2/r = 2mc^2 * exp(-ϵ)

 

Where G is the gravitational constant.

 

This follows gravitational binding energy: https://en.wikipedia.org/wiki/Gravitational_binding_energy

Edited by devin553344
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Posted (edited)

The proton mass energy from strain energy is:

 

ϵ = (9/2 * ђc/(εK^2e^2))^1/2

 

mc^2 = 2/9 * εK^2e^2/r * ϵ^2

 

Where ϵ is the logarithmic strain, ђ is the reduced Planck's constant, c is the speed of light, ε is the permittivity of free space, K is the electric constant, e is the elementary charge, m is the mass of the proton, r is the "reduced" Compton wavelength of the proton.

 

The gravitation then is a leak of the curvature of the matter energy:

 

Gm^2/r = mc^2 * exp(-ϵ)

 

Where G is the gravitational constant.

Edited by devin553344
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Posted (edited)

Still working on this: To unify charge I find that the elementary charge is the same for mass valleys (Planck's constant) as it is for charge hills (electric) in value. Since I have already defined the fine structure types as logarithmic strains for the electron and proton, then I must define the base strain for the charge to Planck relationship. I will do that now. For any cross section of a wave, a distance of 4 gets deformed into two pi leaving the deformation as two pi minus 4. The original length is 1.0:

 

ђc = e^2/ε * (4ln((2π - 4)/1))^2

 

Where ђ is the reduced Planck constant, c is the speed of light, ε is the permittivity of free space, e is the elementary charge.

Edited by devin553344
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Posted (edited)

If the dimensional analysis is wrong, it is wrong period. There is no two sides to this statement.

Then you have to point out what is wrong, unless your trolling ;) I already showed VictorMedvil on my other theory that it was correct, so he is definitely trolling!

Edited by devin553344
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e^2/r is the energy for instance but you have one numerator of strain weighted by a factor of the squared strain, meaning that the dimensions cannot be justified.

Thanks for the response, I welcome the chance to check my equations. I'm assuming you're talking about the electrical to Planck equation since you mentioned e^2/r, but it's not e^2/r it's e^2/ε which is energy times meters, since ε is the permittivity of free space and the reciprocal of the electrical constant. And ђc is energy times meters also.

 

Also that is not a strain energy equation, it references a curvature adjustment where I've used exponential growth of factors:

 

π + exp(1-2*2^1/2)

 

Where each charge is adjusted by multiplying pi and an exponential factor based on the height of the wave: 1.0, and the distance between heights: 2*2^1/2

Edited by devin553344
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Not what I am reading, anyway you write your strain, the dimensions are not possible to construct the rest energy.

 

OK now I see what you're reading... I only used strain in the strain energy equations for the electron and proton rest energy and also for the length the curvature must escape for gravitation. Anyways the dimensions for the following are energy:

 

mc^2 = εK^2e^2/r * ϵ^2

 

This is the same as energy times meters divided by meters. εK^2e^2 is energy times meters since εK = 1/(4pi) then the remainder is Ke^2 and the strain is squared since it is allowed in strain energy equations:

 

E = 1/2 * V * E * ϵ^2

 

Where V is volume, E is Young's modulus, and ϵ is the strain which is dimensionless. See the strain energy equation here: https://en.wikipedia.org/wiki/Strain_energy

 

And I've used the square root of the fine structure basically for the dimensionless strain.

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You also identified epsilon with the strain ... Start writing the equations clear and we can start a proper discussion,because even if it was permittivity, the dimensions are still not making sense.

Those are two different symbols, one is commonly used for permittivity while the other is used for strain. Sorry for any confusion.

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