Dubbelosix 139 Posted May 11, 2018 Report Share Posted May 11, 2018 (edited) Though I have been writing articles that argued for a varying value for the gravitational charge [math]Gm^2[/math] in this particular case we will take it in the Planck unit in order to describe the mass of a black hole. A question that remains is whether a micro black hole undergoes thermodynamic properties or whether it is highly unstable like we would expect for a small black hole.The radiation from a black hole is the sum of many discrete quantum processes, each one of which represents a single quantum transition from a higher to a lower quantum state. As Loyd Motz makes clear in his ''gravitational charge as a unifying principle,'' just like how the radiation from an atom will cease when every electron in the atom is in its lowest quantum state. Consequently, this would be the lowest quantum state for a gravitationally bound system. To prove this, you can start off with Weisskopf's expression for the self energy of a charged particle arising from the random fluctuations of the field - that self energy manifests itsef as the gravitational charge, or mass itself.Using the Berkenstein entropy for the black hole can be written as[math]S = \ln 2 \frac{kc^3}{\hbar G} A[/math] In which [math]A[/math] is the area of the black hole. There are additional arguments you can make for the black hole entropy and can be given as [math]S = k \frac{Gm^2}{\hbar c}[/math] (Also see Motz in reference). If we define the Rydberg constant in terms of the gravitational coupling constant we get: [math]\mathbf{R} = \frac{\alpha_G}{4 \pi \lambda_0} = \frac{1}{\hbar c}\frac{Gm^2}{4 \pi \lambda_0} = \frac{1}{\hbar c} \frac{Gm^3c}{4 \pi \hbar} = \frac{Gm^2}{\hbar c}\frac{p}{4 \pi \hbar}[/math] Even though the Rydberg constant was first applied to hydrogen atoms, it could be derived from fundamental concepts (according to Bohr). In which case we may hypothesize energy levels: [math]\frac{1}{\Delta \lambda} = \mathbf{R}(\frac{1}{n^2_1} - \frac{1}{n^2_2})[/math] Plugging in the last expressions we get an energy equation: [math]\Delta E_G = \frac{n\hbar c}{\Delta \lambda} = \frac{1}{4 \pi }\frac{m_0v^2}{\sqrt{1 - \frac{v^2}{c^2}}} = \frac{1}{4 \pi \lambda_0}(\frac{Gm^2}{n^2_1} - \frac{Gm^2}{n^2_2}) = \frac{p}{4 \pi \hbar}(\frac{Gm^2}{n^2_1} - \frac{Gm^2}{n^2_2})[/math] In fact, I wondered immediately if there are applications of this with the micro black hole and maybe in regards to its energy levels. We start with the equation [math]S = k \frac{Gm^2}{\hbar c}[/math] Where the entropy has taken on the dimensions of the Boltzmann constant. Notice, the de Broglie relationship of wavelength to matter is [math]\frac{1}{\lambda} = \frac{\gamma m_0 v}{\hbar} = \frac{1}{\hbar} \frac{m_0v}{(1 - \frac{v^2}{c^2})}[/math] which is the form we have have used, but in previous work I have identified a gravitational fine structure to the energy levels of a modified Rydberg constant [math]\frac{1}{\Delta \lambda} = \mathbf{R}(\frac{1}{n^2_1} - \frac{1}{n^2_2})[/math] It led to a Rydberg constant which was basically a gravitational fine structure weighted by a wavelength and a factor of [math]4 \pi[/math]. [math]\mathbf{R} = \frac{\alpha_G}{4 \pi \lambda_0} = \frac{1}{\hbar c}\frac{Gm^2}{4 \pi \lambda_0} = \frac{1}{\hbar c} \frac{Gm^3c}{4 \pi \hbar} = \frac{Gm^2}{\hbar c}\frac{p}{4 \pi \hbar}[/math] Clearly there are relationships here with the chosen definition of entropy [math]S = k \frac{Gm^2}{\hbar c}[/math] And an additional similarity appears within the Bekenstein value for the entropy [math]S = k\frac{c^3 A }{4 \pi \hbar G}[/math] Where the factor of [math]4 \pi[/math] has appeared. There will be ways to unify these things together I just have a feeling about it. I am certainly going to see over next few days If I can find a way to do that. Edited May 12, 2018 by Dubbelosix Quote Link to post Share on other sites

Farsight 3,504 Posted May 29, 2018 Report Share Posted May 29, 2018 I would recommend you look into something other than this, Dubbelosix. I say that because I've looked closely at Hawking’s papers, such as particle creation by black holes dating from 1975. He said one of the particles has negative energy relative to infinity, and that the other particle of the pair “having a positive energy, can escape to infinity where it constitutes a part of the thermal emission described above”. Have you ever seen a negative-energy particle? Me neither. It’s a fairy tale and Hawking knew it. That’s why he also offered an alternative "explanation", namely this: “positive energy particles crossing the horizon on past directed world-lines and then being scattered on to future-directed world-lines by the gravitational field”. That’s particles from the future travelling back in time and bouncing off a gravitational field to become ordinary particles. It’s an even bigger fairy tale, and it’s doubtless why Hawking said “it should be emphasized that these pictures of the mechanism responsible for the thermal emission and area decrease are heuristic only and should not be taken too literally”. Quote Link to post Share on other sites

Farsight 3,504 Posted June 4, 2018 Report Share Posted June 4, 2018 (edited) Hello Farsight, I left a comment to you on my blog. I explained there, that there is truth behind Hawking radiation, insomuch we have seen their analogues using sound waves (phonons). If you're talking about observation of quantum Hawking radiation and its entanglement in an analogue black hole by Jeff Steinhauer, that analogy is the waterfall analogy, which is wrong. A gravitational field alters the motion of light and matter through space, it doesn’t make space fall down. We do not live in some Chicken-Little world where the sky is falling in. Edited June 4, 2018 by Farsight Quote Link to post Share on other sites

Farsight 3,504 Posted June 18, 2018 Report Share Posted June 18, 2018 (edited) Now the question still, must remain, unanswered as an anomaly... ''why did the universe prefer matter over antimatter?''It doesn't. Positronium is an "exotic atom". It's comprosed of both matter and antimatter. And it's also described a "light hydrogen". Guess what. Hydrogen is an exotic atom too. PS: the sonic analogy for a black hole is wrong, and black holes don't have a handedness. Edited June 18, 2018 by Farsight Quote Link to post Share on other sites

VictorMedvil 331 Posted June 29, 2018 Report Share Posted June 29, 2018 Still at it I see Dubbleosix just accept the Kerr-Newman Metric and the Superiority of GR over QM and we can be done with this........ Obviously Einstein's equation's Solutions explain everything to do with a BH..... Lol =) Quote Link to post Share on other sites

Super Polymath 29 Posted June 29, 2018 Report Share Posted June 29, 2018 No you don't want to define anything in particular pertaining to the unitary value, it has to remain undefined. Einstein was a front for the results of Tesla's experiments & what Hogh Von Koch, Mandelbrot, & even William James Sidis were brushing on at or around that time. So was QM, & both world wars for that matter. It was the arithmetic of the Greco Roman Philosophers up until 1 AD that acquired & buried the Holy Grail under fronts, the fall of Rome, the Black Plague. Quote Link to post Share on other sites

VictorMedvil 331 Posted June 29, 2018 Report Share Posted June 29, 2018 (edited) No you don't want to define anything in particular pertaining to the unitary value, it has to remain undefined. Einstein was a front for the results of Tesla's experiments & what Hogh Von Koch, Mandelbrot, & even William James Sidis were brushing on at or around that time. So was QM, & both world wars for that matter. It was the arithmetic of the Greco Roman Philosophers up until 1 AD that acquired & buried the Holy Grail under fronts, the fall of Rome, the Black Plague. are we going to storm Dubbelosix's mathematical chamber of Solitude again? *begins to plan the siege and bring in the siege equipment* Edited June 29, 2018 by VictorMedvil Quote Link to post Share on other sites

Super Polymath 29 Posted June 29, 2018 Report Share Posted June 29, 2018 There is one constant inertial pattern seen in flowers, diamonds, & all in nature. There is nothing that is not in motion, there was no original motion, only one constant pendulum with no original push. The reason is because reality is dubious, in means out from one perspective, out means in from the other, think of the qubits as microdot marbles, half out half in from one perspective which has no real objective validity over the other other than that's the one you happen to have. Between each marble is an exponentially smaller set of inversive marbles to fill in the curve (pi) at every angle, between each of those is an even exponentially smaller set, etc etc ad infinitum. Do they ever make contact? Not in this reality, but this reality is the result of a non-origin constant, in which the deleterious di-brane consumes itself like an infinitely long snake eating it's own tail. I told you how to graph this pattern where the scalar metric changes as it pertains to entanglement & superluminal galactic scattering here Quote Link to post Share on other sites

VictorMedvil 331 Posted June 29, 2018 Report Share Posted June 29, 2018 (edited) There is one constant inertial pattern seen in flowers, diamonds, & all in nature. There is nothing that is not in motion, there was no original motion, only one constant pendulum with no original push. The reason is because reality is dubious, in means out from one perspective, out means in from the other, think of the qubits as microdot marbles, half out half in from one perspective which has no real objective validity over the other other than that's the one you happen to have. Between each marble is an exponentially smaller set of inversive marbles to fill in the curve (pi) at every angle, between each of those is an even exponentially smaller set, etc etc ad infinitum. Do they ever make contact? Not in this reality, but this reality is the result of a non-origin constant, in which the deleterious di-brane consumes itself like an infinitely long snake eating it's own tail. I told you how to graph this pattern where the scalar metric changes as it pertains to entanglement & superluminal galactic scattering here I still don't have a Lagrangian or L value for Quantum entanglement your guess is as good as mine. You are welcome to speculate on the dynamics of the QE system because it was never solved, but I was impressed you have almost completed a Gauge and unitary group for your theory. Edited June 29, 2018 by VictorMedvil Quote Link to post Share on other sites

Super Polymath 29 Posted June 29, 2018 Report Share Posted June 29, 2018 I still don't have a Lagrangian or L value for Quantum entanglement your guess is as good as mine. You are welcome to speculate on the dynamics of the QE system because it was never solved, but I was impressed you have almost completed a Gauge and unitary group for your theory.When you compact the photons the lagrangian is the redshifted photon ether between the heavier particles that result from neutrally charged ultra-blue shift photons that's the medium that the gw wave propagates through the heavier particles dilate the time, & the planck metric conforms it gets smaller with each photon compactment there's 33 of them Quote Link to post Share on other sites

Super Polymath 29 Posted June 29, 2018 Report Share Posted June 29, 2018 reducing from the planck length per photon compactment's 1/4^33 was how I got to the anti-proton/neutron/proton's schwarzschild radius of (n)e-54 meters from 1.6e-35 (lp) meters Quote Link to post Share on other sites

VictorMedvil 331 Posted June 29, 2018 Report Share Posted June 29, 2018 When you compact the photons the lagrangian is the redshifted photon ether between the heavier particles that result from neutrally charged ultra-blue shift photons that's the medium that the gw wave propagates through the heavier particles dilate the time, & the planck metric conforms it gets smaller with each photon compactment there's 33 of themWe are really going to do this to Dubbel again, LOL, alright I am in. Virtual photons could be a solution but I need the dynamics of the effect that photons have passing through time-space and their effects on Time-space, so you say it is time dilation upon space? Quote Link to post Share on other sites

Super Polymath 29 Posted June 29, 2018 Report Share Posted June 29, 2018 We are really going to do this to Dubbel again, LOL, alright I am in. Virtual photons could be a solution but I need the dynamics of the effect that photons have passing through time-space and their effects on Time-space, so you say it is time dilation upon space?You read the thread Quote Link to post Share on other sites

VictorMedvil 331 Posted June 29, 2018 Report Share Posted June 29, 2018 reducing from the planck length per photon compactment's 1/4^33 was how I got to the anti-proton/neutron/proton's schwarzschild radius of (n)e-54 meters from 1.6e-35 (lp) meters You mapped a Photon's Schwarzchild Radius interesting, that would be less than a Planck length Quote Link to post Share on other sites

Super Polymath 29 Posted June 29, 2018 Report Share Posted June 29, 2018 Quote Link to post Share on other sites

Super Polymath 29 Posted June 29, 2018 Report Share Posted June 29, 2018 (edited) You mapped a Photon's Schwarzchild Radius interesting, that would be less than a Planck lengthNo the photon's is the planck metric the transformations per plot! the sphere inversions! The schwarzschild radii of those gw ripples would be incalculably infinitesimal. You're trolling me It's only when you get to the 33rd compactment that you get the singular transformation per plot of the anti-proton that becomes the neutron that becomes the proton that gets stuck in that positive charge by electrons in a hydrogen medium Edited June 29, 2018 by Super Polymath Quote Link to post Share on other sites

VictorMedvil 331 Posted June 29, 2018 Report Share Posted June 29, 2018 (edited) No the photon's is the planck metric the transformations per plot! the sphere inversions! The schwarzschild radii of those gw ripples would be incalculably infinitesimal. You're trolling me That's what I am saying the Schwarzchild radius would be very small much smaller than a Planck length for a photon, the gravitational effects of it would be noticed on levels much smaller than a Planck length I have speculated before that Photon may be "Electromagnetic Black-holes" being just a black-hole that is caused from the energy of a photon without anything to push against it besides directional Kinetic Energy or momentum, you could be on to something saying that Photon's could have packets that are smaller than they are that are like BH's. Edited June 29, 2018 by VictorMedvil Quote Link to post Share on other sites

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