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Self Siphoning Water

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Below is depicted a straight tube closed at one end and open at the other filled with fluid. The lower open end of the tube terminates beneath the surface of the fluid in the resevoir and the upper end is closed, preventing normal atmospheric pressure from acting on it. There is no externally applied magnetic field and gravity acting on the fluid is uniform (in the tube and the resevoir). In this situation nothing will happen.... the fluid level within the tube will not rise or fall. Gravity acting on the fluid is uniform (in the tube and the resevoir) and normal atmospheric pressure coming to bear on the surface of the fluid in the resevoir will exert pressure at the base of the water column created by the tube, keeping the water from just falling into the resevoir (as it would in a vacuum). The fluid will remain at rest. The sum of all the equal and opposite forces acting on the system will be zero.... static equilibrium.

Edited by Aemilius
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It would mean more to people if they took the time to do the math themselves.

I’m certain this perpetual motion machine won’t work.   I think I see a simple physics mistake that caused you to think it might, Jim. Though one would intuitively think, as you do, that the pressure

The height in both would be equal. I think Craig did well explaining why.   To find the height divide the pressure inside the container (at the top) by the pressure outside. Subtract that result fro

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Below is depicted the same straight tube closed at one end and open at the other filled with fluid. The lower open end of the tube terminates beneath the surface of the fluid in the resevoir and the upper end is closed as before, preventing normal atmospheric pressure from acting on it, but now with the 5 Tesla permanent magnet installed around it at about the middle of the tube providing an externally applied magnetic field. The fluid at rest within the tube immediately above the externally applied magnetic field will be diamagnetically repelled upward, and the fluid within the tube at rest immediately below the externally applied magnetic field will be diamagnetically repelled downward with a net gain of zero in either upward or downward force. In this situation nothing will happen.... the fluid level within the tube will not rise or fall. Gravity acting on the fluid is uniform (in the tube and the resevoir) and normal atmospheric pressure coming to bear on the surface of the fluid in the resevoir will exert pressure at the base of the water column created by the tube, keeping the water from just falling into the resevoir (as it would in a vacuum). Essentially it will behave just as if the magnet was never installed, with the same result as before.... The fluid will remain at rest within the tube. The sum of all the equal and opposite forces acting on the system will be zero.... static equilibrium.

Edited by Aemilius
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I could continue to explore this, but at this point (with reference to posts 34 and 36), I'm just going to go ahead and jump to the conclusion that....

No imposition of any externally applied magnetic field any where along the length of the siphon in this scenario will result in any tendency on the part of the diamagnetic fluid within the tube to move in one direction or the other, whether the fluid be at rest or in motion.

Fluid at rest within the siphon tube. Magnet installed on the right.... No effect.

Fluid at rest within the siphon tube. Magnet installed on the left.... No effect.

Fluid in motion within the siphon tube. Magnet installed on the right.... No effect.

Fluid in motion within the siphon tube. Magnet installed on the left.... No effect.

Edited by Aemilius
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Sorry for my knee jerk response to your suggestion. You're right. The idea I'm exploring, though similar, is different from the one that went before. It would be a good idea for me to start another thread for it.

Edited by Aemilius

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