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Partical Pressures, again


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The partical pressure of methane is 0.175 atm and that of oxeygen is 0.125 in a mixture of two gases.

a) find mole fraction of each gas in the mixture.

:hihi: if the mixture occupies a volume of 10.5L at 65 C, calculate the total number of moles of gas in the mixture.

c) Calculate number of grams of each gas in the mixture.

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Ok well first off it is partial pressure, referring to the amount of pressure each element present contributes to the overall pressure. So the total pressure in this case is just the sum of the partial pressures:

0.175 + 0.125 = 0.300 atm


Now you can construct a ratio of partial pressure to the total pressure and this will give the fraction of each gas present by number (moles).


Now work that out and attempt the next two.

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