modest Posted May 23, 2009 Report Share Posted May 23, 2009 we want the given distance each car travels is the same , equal The work energy and distance traveled for each car being equal would mean the total friction is equal (regardless of how fast they go or how far they coast or anything else) In your example friction is 0.05N so both cars would go d=W/f (=.98 joules / .05 N) 19.6 meters. The purpose of this lab, however, is to get the cars to go as far as possible—not to get them all to go the same distance. As such, I'm curious what you're trying to calculate above. ~modest Quote Link to comment Share on other sites More sharing options...
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