BiochemC Posted February 13, 2007 Report Share Posted February 13, 2007 Please help with this question!I'm not good at calculations, but i found the Vmax through my graph,vmax=0.909 or 1/Vmax=1.10 question: if the enzyme has a molecular weight of 56,000 and was present in the assays above at a concentration of 4.5ug/ml, calculate the turnover number and the enzyme efficiency in the absence of ethanol. i know Kcat= Vmax/[Etotal] however i dont know how to calculate the etotal, this may be simple math, but i'm a 4th year bio student, and my chem is rusty!thanks Quote Link to comment Share on other sites More sharing options...
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