Jump to content
Science Forums

devin553344

Members
  • Content Count

    548
  • Joined

  • Last visited

  • Days Won

    2

Posts posted by devin553344

  1. I've been working on ways to prove my strong force ideas and realized I may need superconductors to do that so I looked online and found the Gravito-London moment experiments which disappeared behind NASA 10-15 years ago https://www.sciencedaily.com/releases/2006/03/060325232140.htm. Then I realized that the effect was basically concentrating electrons. So I realized I may be able to produce gravitational effects with spinning capacitor disks and found it online in Russia:

     

     

  2. I have the finished theory. I worked out precision values for the electric fields, magnetic moment, gravitation and matter fields using the same inner and outer charge radius for the neutron proton and electron. Again for references please contact me as file size is a limit here.

     

    edit: I've updated the theory with all the current solutions for mass and gravity. Had to study it for a while to get where I'm at in the calculations. They are more accurate now.

     

     

     

     

     

    20210501 Wave-Diode Theory.pdf

  3. On 10/23/2020 at 5:43 PM, devin553344 said:

    I have been working on the magnetic moment equation to unify that with the charge and charge radius of the stable particles (electron and proton). I have finished it. This theory unifies, matter, electric charge, magnetic moment, gravitation. It does this via the wave-diode equality using the Shockley diode equation, it also uses the Peltier effect of reverse thermal flow. Here is the file:

     

     

    There is a slight typo in this file, the electron gravitational degrees of freedom is 9, where the proton is 12. Also the neutron can be described with this theory also, using  charge radius of 1.00559957187091E-15 meters and 10 degrees of freedom.

    Here's the corrected file:

     

     

  4. I have been working on the magnetic moment equation to unify that with the charge and charge radius of the stable particles (electron and proton). I have finished it. This theory unifies, matter, electric charge, magnetic moment, gravitation. It does this via the wave-diode equality using the Shockley diode equation, it also uses the Peltier effect of reverse thermal flow. Here is the file:

     

    20201001 Wave-Diode Theory.pdf

  5. I had some problems with the theory since electrons have no apparent charge radius, I found the charge radius of the electron is the electron wavelength. I worked out the equations to support the measured charge radius of the proton and the wavelength of the electron.

    This is a wave-diode equivalence theory. It states that waves behave like diodes with p-n junctions which provides an electric charge as a reverse biased amperage. The Shockley diode equation is used to describe the different forces. There is also a reverse amperage heat conducted in reverse of the electric charge via the Peltier effect. This creates the gravitation for the particles. The strong force is a 4 dimensional wave force that is strongest at the wave peaks. The charge radii for the particles is verified via the radii of the Hydrogen atom for the electron and the Deuteron atom for the proton and neutron.

    I'm using boiling points to describe particle stability.

     

  6. On 10/5/2020 at 11:04 AM, andrewgray said:

    I'm glad you asked this question, Devin.  You see, it is not residual charge that I am talking about.  It is residual electric force.  There is a big difference.  What I am saying is that atoms are completely made up of protons and electrons (each neutron is a proton and electron combo).  Then, between two bodies that have the save number of protons and electrons (neutral), the attractive electrical forces are ever, ever, ever, ever so slightly greater than the repulsive electrical forces by one part in Ten-36.gif !  This says nothing about charge.  We are only dealing with attractive and repulsive electrical force.  the two bodies  have the same number of positive and negative charges.  But the attractive electrical forces are ever so slightly larger than the repulsive electrical forces. 

    Calculations?  OK. An example:

    Take two hydrogen atoms, A and B ,  separated by one meter.  They each have one electron and one proton. Now the attractive electrical forces between them are the e-p and the p-e electrical forces.  The repulsive electrical forces would be the e-e and the p- electrical forces.

    The attractive and repulsive electrical forces would be about:

    GravityExample.png

    The magnitude of these two numbers are experimentally the same!  They only differ by one part in Ten-36.gif (see the last red digit).  You could not measure this difference experimentally!  But this "teensy weensy tee-niney" difference in magnitude is enough to give the two hydrogen atoms a gravitational attraction!

    One last thing.  Remember, the proton and electron are completely different "animals".  The proton is more than a thousand times more massive than the electron.  They both pulsate.  They probably pulsate differently...

    So... it does not seem unreasonable, that out to some decimal place, the attractive and repulsive electrical forces are different.  Devin, do you believe they are the same out past 36 decimal places? Do you believe they are the same out past a 1000 decimal places?  Out past a 10,000 decimal places?  They are "different animals".  In my mind, no one in their right mind would believe this! (Perhaps electron-positron attractive/repulsive forces go out more decimal places the same, but not electron-proton ones!)

     

    Andrew Ancel Gray

    PS.  Now on with Gravity?

    PSS.  There is gravitational repulsion!  By symmetry, antimatter would repel "regular matter" gravitationally, not attract, contradicting Einstein.

    So Devin, do you at least understand what I am saying (but maybe not agree?) ???

    Andrew, it would appear that in order to understand electric force, you must first understand how it works. Electric force is a function of electric charge. Without electric charge force does not exist. In fact without an imbalance in charge, there is no force to even consider. Which is why I cannot consider your idea.

    Not to mention the fact that the electric escape energy (force) is subtracted or added to the mass of the parts of the electrons and protons. Which is why there is no additional energy floating around either. So there's no force for your idea. Calculations? Look at hydrogen, the force of the electron is removed from the mass of the electron and proton, this is the basic principle everyone accepts.

    Keep working on it, but you're headed in the wrong direction here.

  7. On 10/2/2020 at 1:28 PM, andrewgray said:

    Devin,

    Correct.

    Correct.

    What gravity is... is a Residual Electrical Force.  That is, (between 2 bodies) the sum of the electrical attractive forces plus the sum of the electrical repulsive forces is very close to zero, but not quite!   The sum of the electrical attractive forces plus the sum of the electrical repulsive forces is close to zero by one part in Ten-36.gif !  That is unimaginably close to zero!  But that extremely, extremely small left-over-force is enough to make gravity.

    We cannot say what the residual charges are.  Only that the sum of the electical attractive forces plus the electrical repulsive forces is extremely, extremely close to zero, but ever so slightly attractive!   And by symmetry, that would make anti-matter gravitationally repulsive to matter, contradicting Einstein.

    Devin,

    Correct.

    So is the "gravitational mass" invariant, since large gravitational bodies in the universe move "slowly" relativity-wise.  The gravitational mass would be proportional to the number of proton-electron pairs a body possessed (remembering to count each of its neutrons as one proton and one electron!)

    So that means that the gravitational force is indeed a vector force... so that means that we will have to deal with Einstein, his equivalence principle, Spacetime Curvature, and his General Relativity!  Coming!

    Andrew Ancel Gray

    I think you're missing the point, how is it that the sun, planets, moons all attract, but none repel, so your idea is that there is some charge to the sun, planets and moons. Have you worked out any math or calculations? Probably not cause then you would see that your idea is invalid.

  8. I have some new equations, I have been examining the math and looking to see if the math will support my idea. Basically a wave is also a diode. Therefore the wave-particle duality should support diode physics and work with the Shockley diode equation. What I found is this:

    Charge radius:

    rc = 4r/(2pi)

    Where rc is the charge radius of the particle (for the proton it's 8.412E-16 meters), r is the wavelength of the particle.

    Electric charge:

    Ke^2/rc^4 = hc/r^4 * exp(-(hc)/(kb))

    Where K is the electric constant, e is the elementary charge, h is the Planck constant, c is the speed of light, k is the Boltzmann constant, b is the Wien displacement constant.

    Electron gravitation (uses 4 dimensional n-sphere volume solid angle):

    Gm^2/rc^4 = Ke^2/rc^4 * exp(-1/2*pi^2*4*(hc)/(kb))

    Where G is the gravitational constant, m is the mass of the particle.

    Proton/Neutron gravitation (uses 3 dimensional n-sphere volume solid angle):

    Gm^2/rc^4 = Ke^2/rc^4 * exp(-4/3*pi*4*(hc)/(kb))

    Cheers,

    Devin

  9. I am proposing a Peltier effect for the gravitation, I will model only the proton, but basically a heat is conducted by the reverse bias amperage of the diode which goes into the Shockley diode equation to calculate a secondary reverse bias amperage for gravitation:

    Again the Proton gravitation is:

    Gm^2/r^5 = hc/r^5 * exp(-hc/(Ke^2) * rC^5/r^5)

    Where G is the gravitational constant, m is the proton mass, r is the wavelength of the proton, h is Planck's constant, c is the speed of light, K is the electric constant, e is the elementary charge, rC is the charge radius of the proton.

  10. I'm working on a better solution using the same idea and have concluded that the temperature relates to the Boltzmann constant and the Wien displacement constant:

    Ke^2/rC^5 = hc/r^5 * exp(-9/2*hc/(hc))

    Where K is the electric constant, e is the elementary charge, rC is the charge radius of the particle, h is Planck's constant, c is the speed of light, r is the wavelength of the particle.

  11. I have been studying theory for about 5 years now and concluded that charge may be a hill of pressure (space-time) and matter a valley of pressure. Both exist in a wave form with positive and negative components created a diode-like p-n junction. And if that is the case then perhaps the Shockley diode equation can be used to describe the reverse-bias amperages that are involved in such hills and valleys. I found that the electron represents 3 degrees of freedom while the proton appears to represent 4 degrees of freedom. The 5 equations that describe matter, electromagnetic, strong force and gravitation of the proton and electron are:

    Proton charge:

    3/5 * Ke^2/rC^4 = hc/rp^4 * exp(-2/4 * 1/g^2)

     

    Where K is the electric constant, e is the elementary charge, rC is the charge radius of the proton at 8.391E-16 meters, h is Planck's constant, c is the speed of light, rp is the Compton wavelength of the proton, exp is the natural exponent, and g is the electromagnetic coupling constant:

    g = ((8pi^2Ke^2)/(hc))^1/2

    Electron charge:

    3/5 * Ke^2/re^4 = hc/re^4 * exp(-2/3 * 1/g^2)

    Where re is the electron Compton wavelength.

    Proton gravitation:

    Gmp^2 = Ke^2 * exp(-12 * 1/g^2 * rC/rp)

    Where mp is the mass of the proton.

    Electron gravitation:

    Gme^2 = Ke^2 * exp(-9 * 1/g^2)

    Where me is the mass of the electron.

    Strong force is the electric kinda of area where the wave is 180 degrees and produces an attractive force (curvature):

    U = hc/r^4 * (rp/2)^3 * exp(-2/8 * 1/g^2)

    Where U is the binding energy of the strong force, Deuteron calculates to 1.784E-13 Joules and large nuclei calculate to 1.23E-12 Joules.

    The Deuteron radius is then:

    rD = rC + rp = 2.16E-15 meters

    The charge radius of the proton might be a wave deformation of the wave distance of two pi divided by the linear distance of 4:

    rp/rC = 2pi/4

    Cheers,

    Devin

  12. I'm adjusting the electron to be basically a 5 dimensional n-sphere (https://en.wikipedia.org/wiki/N-sphere):

     

    hc/(8/3 * π^2 * (re + re)^5) = Ke^2/re^5

     

    Where h is Planck's constant, c is the speed of light, re is the electron wavelength, K is the electric constant, e is the elementary charge.

     

    It's close but slightly off, and it allows the two times the wavelength to be compressed down to the wavelength, created a charge pressure of the wavelength size and a vacuum of mass of the wavelength. The amount it is off appears to relate to an angular kinetic energy similar to the slight off of the proton. This is a 5 dimensional native nature to electromagnetic radiation perhaps. It might not have a strong force since the wavelengths of mass and charge are the same.

     

    The proton is still a 4 dimensional n-sphere:

     

    hc/(2 * π^2 * (rC + rp)^4) = Ke^2/rC^4

     

    You might consider that since the charge radius rC is 2π/4 less than the wavelength of rp that it is a dimensional shift and therefore requires one less dimension than the electron.

     

    The remaining energy that is not balanced works out to the following for either particle (which may relate to the fine structure):

     

    mc^2a^2/(gs*r^n)

     

    Where m is the mass of the particle (either electron or proton), a is the fine structure constant, gs is the g-factor of the particle, r is the wavelength, and n is either 3 or 4 depending on whether it's 4 dimensional or 5 dimensional.

     

    The idea here is that any valley (mass) that exists in space must therefore have an equal and opposite hill (charge). Therefore an equation must exist to describe that equality.

×
×
  • Create New...