pgrmdave Posted December 17, 2004 Report Share Posted December 17, 2004 In this sentance, the number of occurances of each numeral is as follows: 0 = _ , 1 = _ , 2 = _ , 3 = _ , 4 = _ , 5 = _ , 6 = _ , 7 = _ , 8 = _ , and 9 = _ . Have fun solving it! If I remember correctly, there are multiple solutions. Link to comment Share on other sites More sharing options...
Tormod Posted December 17, 2004 Report Share Posted December 17, 2004 Hm...I don't get it. Is this a typical math quiz thingy? Are we supposed to find numbers or letters or what? Link to comment Share on other sites More sharing options...
pgrmdave Posted December 17, 2004 Author Report Share Posted December 17, 2004 well, try to solve it. say you start at the number of 0, well, there's one zero in the sentance, so you would list it as 1 0=1then you move to the ones, there are now two ones, so you list it as 20=11=2then to the twos, there are two twos, so you list it as two0=11=22=2uh-oh, now there are three twos, but if you change it, it will become false... and so on, until you have a workable solution. Link to comment Share on other sites More sharing options...
Tormod Posted December 17, 2004 Report Share Posted December 17, 2004 I would probably fail miserably on any Mensa test. :) Link to comment Share on other sites More sharing options...
Bo Posted December 17, 2004 Report Share Posted December 17, 2004 Spoil of the puzzle ahead!! thanks for the nice puzzle! (i typed in three solutions, that on the other hand appeared to be wrong after all...) the following sollution (i agree that it probably isn't unique) is derived in the following way: if you put 2 ->3, 3->2 x->2, 1->x then the rest of the numbers should be 1. It turns out that x=7 0=11=72=33=24=15=16=17=28=19=1 Bo Link to comment Share on other sites More sharing options...
pgrmdave Posted December 17, 2004 Author Report Share Posted December 17, 2004 Congratulations! It took me an hour of guessing until I stumbled upon the same idea, although I couldn't have explained it so well. Link to comment Share on other sites More sharing options...
Bo Posted December 17, 2004 Report Share Posted December 17, 2004 another puzzle! 0101110311013211013123110231241101413223110 what is the next number in this sequence? (hit: use a similar technique as with pgrmdave's puzzle) Bo Link to comment Share on other sites More sharing options...
sanctus Posted December 17, 2004 Report Share Posted December 17, 2004 The solution is : 1423224110 Stop reading if you don't want to know the solution. there is always an even number of digits, therefore you can make pairs (i. regroupe numbers two by two). the first digit of every pair represents the number of times the second digit appears in the number preceeding. Link to comment Share on other sites More sharing options...
lindagarrette Posted December 19, 2004 Report Share Posted December 19, 2004 I'm trying to find a puzzle someone on this forum presented some time ago that fooled a lot of people. It had to do with a screen of numbers in some graphic context that were arranged in rows and columns. The idea was to pick a number from the screen, click on a button, and the next screen would show the selection you picked and say "try again?" It was not that difficult to figure out the gi mic but was entertaining challenge for a short time. If anyone can remember of knows of it, please send me the web address. Link to comment Share on other sites More sharing options...
Recommended Posts