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Height


Moonchild

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OK, so from the equation PE+KE=E(mechanical), we can derive the following equation: h=v^2/2g Under what conditions/events does this scenario apply?

 

there are 3 assumptions made in such a derivation:

- The kinetic energy is given by 1/2 m v^2

- the potential energy is given by m g h

- no energy is lost.

 

and it describes a particle falling downword, with constant accelarationg g, and perhaps moving with a constant speed in the horizontal direction

 

epecially the point about the potential energy can be altered a bit, e.g. if e include some friction, a form for the potential could be ~ mgh - K v ; where K is some constant. Alterations in the path of the particle would be that the acceleration isn't constant anymore.

 

Bo

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