Latex Practice Ground

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#69 modest

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Posted 25 January 2009 - 05:38 PM

Oh... ok. I was looking at the /frac at the bottom of your post where it asks why it's not rendering. I didn't see the one at the top.

testing...
$\frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28} = 2$

$\frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28} = 2$

why is $/frac{1}{14}$ not rendering right using the latex tags instead of math tags?

I've noticed, though I have no explanation for this, latex tags need spaces where math tags do not. So I'm guessing...

$\frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28} = 2$

$\frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+ \frac{1}{14}+\frac{1}{28} = 2$

Yeah, a space before the "\frac{1}{14}" fixed it. To prevent it rendering you can use [noparse][/noparse] tags...

$\frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+ \frac{1}{14}+\frac{1}{28} = 2$

Sorry 'bout the confusion.

~modest

#70 alexander

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Posted 26 January 2009 - 12:59 PM

why are you guys using the latex tags???!!!???

DEAR PEOPLE!!!

It has come to my attention that you are still using the latex tags, even though they have been deprecated and outdated for quite some time now. I actually left the old engine on to support antiquated syntax in posts, but apparently some people STILL use it! Stop using the latex tags, they are deprecated and use far more resources then the math tags, simply because they don't do any caching!!!

#71 Turtle

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Posted 26 January 2009 - 01:14 PM

why are you guys using the latex tags???!!!???

I can only speak for myself, but I used them because I'm a noobus , and the title of the thread was Latex Practice Ground not Math Practice Ground. Do I take my shirt off, or leave it on for my lashes?

#72 JMJones0424

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Posted 23 February 2009 - 01:04 PM

$u = \frac{v_1 + v_2}{1 + \frac{(v_1 \times v_2)}{c^2}}$

#73 freeztar

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Posted 23 February 2009 - 01:36 PM

$u = \frac{v_1 + v_2}{1 + (v_1 * v_2)c^2}$

Well done Jones!
Another good tag to know is the multiply sign (it looks better than an asterisk).

$3\times4$
$3\times4$

or

$3\cdot4$
$3\cdot4$

#74 alexander

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Posted 23 February 2009 - 02:26 PM

shoot i forgot to finish the updated tutorial...

#75 alexander

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Posted 23 February 2009 - 02:30 PM

oh pheew, i almost did...

btw no comments on the updated tutorial?

#76 alexander

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Posted 23 February 2009 - 03:53 PM

updated a little more today to provide explanations for some math symbols, etc... only things left are widehat, widetilde, and finally to figure out what Pr function is...

#77 modest

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Posted 23 February 2009 - 06:01 PM

I did notice one small thing,

\widetilde{abc} $\overwidetilde{abc}$
\widehat{abc} $\overwidehat{abc}$

A bit over wide But, really, all-around fantastic.

~modest

#78 alexander

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Posted 23 February 2009 - 06:10 PM

yea i gotta solve those issues... i'll get around to it hopefully tomorrow

#79 modest

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Posted 30 May 2009 - 06:52 PM

[ce]6FeO -> 2Fe2O3 + 2Fe[/ce]
[ce]6FeO -> 2Fe_2O_3 + 2Fe[/ce]
[ce]6 FeO -> 2 Fe_2 O_3 + 2 Fe[/ce]
[ce]6FeO \rightarrow 2Fe_2O_3 + 2Fe[/ce]
[ce]FeO -> Fe2O3 + Fe[/ce]
[ce]FeO -> FeO + Fe[/ce]
[ce]FeO[/ce]
[ce]Fe[/ce]
[ce]Se[/ce]
[ce]H[/ce]
[ce]Na[/ce]

I'm at a loss

#80 alexander

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Posted 30 May 2009 - 09:40 PM

somebody messed with something in the plugin again, or someone played with the latex install, i gotta get to tormod, i noticed the ce tags were going crazy things too...

Let me find out what has changed, but something certainly did...

#81 rish209

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Posted 08 June 2012 - 11:19 PM

;$e=mc^2$
WHY WONT LATEX WORK

Edited by rish209, 08 June 2012 - 11:27 PM.

#82 CraigD

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Posted 09 June 2012 - 03:38 PM

;$e=mc^2$
WHY WONT LATEX WORK

'Cause, on forums like ours, you don't tag it with \$...;, but $...$ or [imath]...[/imath].

So $e=mc^2$ renders as $e=mc^2$.

#83 phision

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Posted 10 June 2012 - 06:52 AM

So $e=mc^2$ renders as $e=mc^2$.

Was going to ask why the phrase you entered above wasn't rendered, but after seeing the quote I understand now.

#84 rhertz

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Posted 22 May 2019 - 03:55 PM

$\frac{\dot{T}}{T} (\frac{\ddot{T}}{T} + \frac{kc^2}{a^2}) = \frac{8 \pi G}{3} \int\ [\dot{N} + N\dot{S}_k + N\dot{S}_{ik}] (\frac{8 \pi \hbar \nu^3}{c^3} \frac{1}{\frac{\hbar \nu}{k_BT} - 1} + \frac{8 \pi \hbar \nu^3}{2c^3})\ d\nu$

text to separate

$ab_0$

$a$

$a$

$ac^2$

$k^2 = a^2$

$ab_0$

${\large{\int_{k=0}^{55}}} k dk$

$\int_{k=0}^{55} k dk$

$I(t) = I_0.e^{-\large\frac {t}{\tau_0}}$

$\Gamma_\mu = \large\frac {G_F^2{m_\mu}^5}{192\pi^3}$

$\tau_\mu = \large\frac {\hbar}{\Gamma_\mu}$

[math] \tau_\mu = 6 [\math]

[math] \tau_\mu = \large\frac {192\hbar\pi^3}{G_F^2{m_\mu}^5}[\math]

Edited by rhertz, 24 May 2019 - 11:08 PM.