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Latex Practice Ground


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#1 alexander

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Posted 13 May 2006 - 07:45 PM

This is a thread to practice latex, in case you have no idea what it is, please read our LaTeX tutorial.
I will answer all of your questions in that thread as well, please dont post them here, please dont, i will have to move them...

#2 Tormod

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Posted 22 May 2006 - 06:42 AM

[math]E=mc^2[/math]

About as far as I got.

#3 ronthepon

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Posted 22 May 2006 - 10:52 AM

Testing...

[math] a^b [/math]

#4 ronthepon

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Posted 22 May 2006 - 08:21 PM

[math]\delta \Delta \frac{x}{\vec{x}} [/math][math]\huge a, b \cancel\delta[/math]

god this is a bit nice...

[math]\cancel{a}[/math]

[math] \delta aa \acute{50} ,\etc[/math]

mmmm... so many others to try out!

#5 sanctus

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Posted 23 May 2006 - 02:17 AM

[math]
f(x)=\int_{-\infty}^x\frac{(e^{-t^2})}{\sqrt{\pi^x}}dt
[/math]

#6 ronthepon

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Posted 23 May 2006 - 05:41 AM

[math]\huge \int_{a}^{b}{e^{-14x}^{e}}{dx}[/math]

Will this work?

[math]a^b^c^d^e^f^g^h[/math]

staircase!

[math]\frac{X^5_G}{A_2}[/math]

[math]\huge \frac{1}{\int^{\delta}_{{\delta}{\pi}} {x}^{\frac{987^{\frac{X^5_G}{\int^{a}_{e^{4123}}{x^{\frac{1.24}{L}}}{dx}}}}{\int_{low}^{high}{x^{x^{2e}}dx}}}dx}[/math]

I guess some day or the other, this is going to give up on me. Lets see how much more complex I can make this, before it first shows signs of efficiency weakness.


Any human wanna solve this expression? No! don't run away!

#7 Pyrotex

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Posted 23 May 2006 - 10:11 AM

I guess it is my turn. Lessee...

[math]\Large f(t) = \int_{\small x=0}^{\small x=t}\frac{\sqrt{a x^3 + b x + c^2}}{e^{(c\pi x^2)}} dx\\ \normalsize\text{where a, b, c = integers >0}[/math]

Cool beans!! Hot ****!! Ultimate power!!
Tomorrow... [math]\\ \huge\text{The World!}[/math]

#8 InfiniteNow

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Posted 23 May 2006 - 01:00 PM

Cool beans!! Hot ****!! Ultimate power!!
Tomorrow... [math]\\ \huge\text{The World!}[/math]


Pinky and the Brain reference?

#9 Pyrotex

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Posted 23 May 2006 - 01:01 PM

Pinky and the Brain reference?

Ahhhh!! Pinky!! There you are!!

#10 InfiniteNow

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Posted 23 May 2006 - 01:09 PM

.

Brain: There's only one ride that interests me - the incredible thrill ride of taking over the world!
Pinky: Mmm, I think there's a height requirement for that ride.



#11 InfiniteNow

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Posted 23 May 2006 - 01:19 PM

[LATEX]test(1.\small{01}\normal)={\frac{1}{\infty^\pi} * 14x\sqrt{-1} = \huge{Sweet}[/LATEX]


[LATEX]{\infty}Now[/LATEX] :shade:

#12 Pyrotex

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Posted 23 May 2006 - 01:23 PM

Well done, Pinky!! You have mathematically proven that no matter where you are on Earth, you are no more than 4 blocks away from the nearest Starbucks! Do you realized what this means?!?!?! It means I can...

[math]\huge\text{Take Over the World!!}[/math]

#13 Southtown

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Posted 07 September 2006 - 09:55 AM

[math]$\sim a_0 \sim 1\AA{\rm s}^{-2}$[/math]
Well that's udderly meaningless.

Found it here, per C1ay's news about the dark matter rebuttal.
http://arxiv.org/abs/astro-ph/0606216

#14 Southtown

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Posted 12 September 2006 - 10:09 AM

[math]\left( \sum_i \vec{\alpha}_i \cdot \vec{\nabla}_i + \sum_{i \neq j} \beta_{ij} \delta( \vec{x}_i - \vec{x}_j ) \right) \vec{\Psi} = K \frac{\partial}{\partial t} \vec{\Psi} = iKm \vec{\Psi}[/math]

Courtesy of Doctordick. =)
http://home.jam.rr.c...ain/Explain.htm

#15 Fatstep

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Posted 25 February 2007 - 11:43 AM

[math]\beta \gamma \ArrowBoldRightShort[/math]

#16 Guest_Lambus_*

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Posted 27 April 2007 - 03:51 AM

testing...
[math]\frac{d}{dx} © = 0[/math]

#17 Guest_Lambus_*

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Posted 27 April 2007 - 03:52 AM

testing...
[math]\frac{d}{dx} (x) = 1[/math]