Multipication

[cookietran]

is there a way to distribute xor over multication?

exe t*t^58 = t^? *t^?

[Dubbelosix]

What are you asking, I don't understand your formula?

[Vmedvil2]

 

is there a way to distribute xor over multication?

exe t*t^58 = t^? *t^?

 

t⁵⁹ is the solution as t*t = t² , the exponent just shortens the list of multiplication t * t * t = t³ and so on. t⁵⁸ is just 58 sequences of  t*t  which is the same as saying ∏₀⁵⁸ t * t, thus multiplying t * t⁵⁸ = t⁵⁹

Edited July 29, 2020 by VictorMedvil

[Dubbelosix]

Oh that's what he meant. The exe threw me off, we usually write or either as above of exp.

[Vmedvil2]

Oh that's what he meant. The exe threw me off, we usually write or either as above of exp.

Well I assume that's what he means, i dunno what the EXE means. t^t would be something different if he meant that or t^t^58 =  ∏₀^t t⁵⁸  * t⁵⁸  or   t⁵⁸ * t⁵⁸ , t number of times, which when t = 2 would be 2⁵⁸ * 2⁵⁸

Edited July 29, 2020 by VictorMedvil

[Dubbelosix]

Well I assume that's what he means, i dunno what the EXE means. t^t would be something different if he meant that or t^t^58 = ∏₀^t t⁵⁸ * t⁵⁸ or t⁵⁸ * t⁵⁸ , t number of times, which when t = 2 would be 2⁵⁸ * 2⁵⁸

Indeed. We can relax I suppose, but the poster should be more clear.