Jump to content


Photo
- - - - -

Doppler Effect Of Gravitational Field

Doppler Speed of light Gravitational field

  • Please log in to reply
148 replies to this topic

#137 OceanBreeze

OceanBreeze

    Creating

  • Moderators
  • 1156 posts

Posted 24 March 2020 - 10:36 AM

Time to move this to alternate theories.


  • exchemist and VictorMedvil like this

#138 TonyYuan2020

TonyYuan2020

    Questioning

  • Members
  • PipPipPipPip
  • 130 posts

Posted 24 March 2020 - 10:47 AM

Time to move this to alternate theories.

Thank you so much for keeping up with my thread and I will continue to work for it.



#139 TonyYuan2020

TonyYuan2020

    Questioning

  • Members
  • PipPipPipPip
  • 130 posts

Posted 25 March 2020 - 09:41 AM

To summarize the recent discussions:
1.In a uniform gravitational field, the speed of light does not change.
2.At different gravitational field strengths, the speed of light is different.
(1)The stronger the gravitational field, the slower the light speed, and the weaker the gravitational field, the faster the light speed.
(2)Light passing through an uneven gravitational field will cause refraction bending due to different speeds.
3.The Doppler effect exists in the gravitational field.
(1)If away from each other, the strength of the gravitational field will be smaller than that at the relatively stationary state, the larger the relative speed , the weaker the gravitational field;
(2)If close to each other, the strength of the gravitational field will be greater than that at the relatively stationary state, the greater the relative speed, the stronger the gravitational field.
4.There is a uniform gravitational field on the surface of the earth, and the speed of light measured in different directions is constant.
5.To calculate the motion of celestial bodies with universal ravitation, the Doppler effect of the gravitational field needs to be considered. The greater the relative speed, the more pronounced.
 
 

Edited by TonyYuan2020, 25 March 2020 - 09:42 AM.


#140 TonyYuan2020

TonyYuan2020

    Questioning

  • Members
  • PipPipPipPip
  • 130 posts

Posted 25 March 2020 - 10:09 AM

Doppler Effect Of Gravitational Field. It will unify classical physics and relativity.
https://photos.app.g...YpK61mguFxFKiy5

1.In a uniform gravitational field, the speed of light does not change.
2.At different gravitational field strengths, the speed of light is different.
(1)The stronger the gravitational field, the slower the light speed, and the weaker the gravitational field, the faster the light speed.
(2)Light passing through an uneven gravitational field will cause refraction bending due to different speeds.
3.The Doppler effect exists in the gravitational field.
(1)If away from each other, the strength of the gravitational field will be smaller than that at the relatively stationary state, the larger the relative speed , the weaker the gravitational field;
(2)If close to each other, the strength of the gravitational field will be greater than that at the relatively stationary state, the greater the relative speed, the stronger the gravitational field.
4.There is a uniform gravitational field on the surface of the earth, and the speed of light measured in different directions is constant.
5.To calculate the motion of celestial bodies with universal ravitation, the Doppler effect of the gravitational field needs to be considered. The greater the relative speed, the more pronounced.

https://photos.app.goo.gl/hxMZR9vwv6sWLjcbA

 

The Doppler effect is classical physics. This theory can be applied to mechanical waves, electromagnetic waves, and gravitational waves as well. Although gravitational waves are not mentioned in classical physics, the model I created for gravitational waves is a model of classical physics. The knowledge you need to understand it does not go beyond the scope of classical physics.

 
The Doppler effect of the gravitational field I described is clear. The gravitational formula needs to include a velocity (not speed) parameter. F = G * M * m / r ^ 2 * f (x), x is the speed of light minus the component of v in the c direction.
When x = 0, it is the gravitational strength when it is relatively stationary, F = G * M * m / r ^ 2, so f (0) = 1.
When x = c, the gravitational wave cannot reach the object, so F = 0, so f © = 0.
F = G * M * m / r ^ 2 * f(x) = (G * M * m / r ^ 2) * x / c .

Edited by TonyYuan2020, 26 March 2020 - 08:47 PM.


#141 OceanBreeze

OceanBreeze

    Creating

  • Moderators
  • 1156 posts

Posted 26 March 2020 - 03:21 AM

moderator note: merging this to the other thread as this post is just a repeat of the last post in that thread



#142 ralfcis

ralfcis

    Creating

  • Members
  • PipPipPipPipPipPipPip
  • 1165 posts

Posted 26 March 2020 - 10:39 AM

Ever been to the sciforums? That is one loony bin. Either all but one are insane or I'm insane.


Edited by ralfcis, 26 March 2020 - 10:29 PM.


#143 TonyYuan2020

TonyYuan2020

    Questioning

  • Members
  • PipPipPipPip
  • 130 posts

Posted 26 March 2020 - 07:25 PM

Ever been to the sciforums? That is one loony bin. Either all but one is insane or I'm insane.

They are also just a group of science enthusiasts. If you want to express different opinions on their territory, it is equivalent to robbing them of their territory.



#144 Dubbelosix

Dubbelosix

    Creating

  • Members
  • PipPipPipPipPipPipPip
  • 3494 posts

Posted 26 March 2020 - 08:04 PM

They are also just a group of science enthusiasts. If you want to express different opinions on their territory, it is equivalent to robbing them of their territory.

 

As enthusiastic as they believe they are, they don't really know much about physics. But you are right, if you drop any kind of sense on their territory that challenges what they think they know, they will rob you of your posts, belittle you and then mark you as a pseudoscientific troll. 



#145 TonyYuan2020

TonyYuan2020

    Questioning

  • Members
  • PipPipPipPip
  • 130 posts

Posted 27 March 2020 - 08:55 AM

Many people may think that the gravity between the planet and the sun depends only on their mass and distance. GR tells us that the huge mass of the sun will cause a huge space-time curvature, which will advance forward as the sun moves, and the distant space will gradually return to flat. So for a certain space position that the sun passes, his space-time will go through a process as shown in the figure.
https://photos.app.goo.gl/QK2czMKm8wZ8di2c8
It looks very much like a wave, which is as fast as light. GR also tells us that the planets only move along geodesics in curved space. But you should think that the space-time curvature will also occur around the planet, and the curvature of the planet and the curvature caused by the sun will be superimposed on each other, as shown in the figure.
https://photos.app.goo.gl/bBaCgHcamdvSxaoh7

We know that the planet is orbiting the sun, so will this superimposed curved shape be related to the movement of the sun and the planet?
1. Assuming the sun and the earth are relatively still, we can get a curved shape.
2. Assuming there have a relative velocity between the sun and the earth, we can get a curved shape again.
Do you think their shapes will be the same? Obviously different! Since they are different, the phenomenon of gravity caused by time and space bending will not be the same! Therefore, when calculating the gravitational force between two objects, we must take their respective velocities into account.
So general relativity also supports the Doppler effect of gravitational fields. In other words, adding the Doppler effect to universal gravity is equivalent to general relativity.
F = (G*M*m / r^2) * f(x) = (G*M*m / r^2) * (x / c) . x is the speed of light c minus the component of v in the c direction.
https://photos.app.g...qx1UGW8LkRs7g4A
 

Edited by TonyYuan2020, 27 March 2020 - 09:04 AM.


#146 TonyYuan2020

TonyYuan2020

    Questioning

  • Members
  • PipPipPipPip
  • 130 posts

Posted 27 March 2020 - 05:48 PM

F = (G*M*m / r^2) * f(x) = (G*M*m / r^2) * (x / c)
If the Doppler effect of the gravitational field is taken into account to calculate the precession of Mercury, will it be consistent with the observed results?

I need your help, come on.


Edited by TonyYuan2020, 27 March 2020 - 06:01 PM.


#147 exchemist

exchemist

    Creating

  • Members
  • PipPipPipPipPipPipPip
  • 2898 posts

Posted 28 March 2020 - 03:32 AM

F = (G*M*m / r^2) * f(x) = (G*M*m / r^2) * (x / c)
If the Doppler effect of the gravitational field is taken into account to calculate the precession of Mercury, will it be consistent with the observed results?

I need your help, come on.

Well, you need help, certainly.  :winknudge:



#148 TonyYuan2020

TonyYuan2020

    Questioning

  • Members
  • PipPipPipPip
  • 130 posts

Posted 28 March 2020 - 04:28 AM

The Doppler effect of the gravitational field can well explain the deviation of Mercury precession.
https://photos.app.goo.gl/e7QhPSgN6FrQs9tL7

The calculation of the precession of Mercury's perihelion is actually based on Newton's law. The result is that precession per century = 5,557.62". 90% of this is caused by the precession of the coordinate system. The perturbations caused by the perturbations of Venus, Earth, and Jupiter are actually 5,600.73", which is subtracted to 43.11" per century.

If the Doppler effect of the gravitational field was taken into account in the calculation, there would be no 43.11 "deviation.



#149 TonyYuan2020

TonyYuan2020

    Questioning

  • Members
  • PipPipPipPip
  • 130 posts

Posted 28 March 2020 - 09:09 AM

To study astrophysics, you must have good tools. I plan to write a program for celestial movement. The motion between any stars can be accurately simulated and their orbits can be drawn. In this way, Mercury precession can be easily analyzed through the program. I would like to know if my model of the gravitational field Doppler effect is accurate. Science is really interesting.





Also tagged with one or more of these keywords: Doppler, Speed of light, Gravitational field