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Explaining The Electromagnetic Fields Of The Earth


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#52 devin553344

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Posted 21 December 2019 - 03:44 PM

I got my log strain wrong for the proton. Its 3s instead of s^3. So I'm still working on it.


Edited by devin553344, 21 December 2019 - 03:44 PM.


#53 devin553344

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Posted 23 December 2019 - 02:25 AM

Still working on this: OK I've been working on equal and opposite reactions and think I may have found another that also describes the wave particle duality. Radius, grows and shrinks in equal and opposite directions. Such that the particle has a particle radius of rS and a wave radius of the wavelength. The proton then has log strain and the electron carries the same kinetic energy as the electron orbiting the proton to make the neutron:

 

rK = (8πGKe^2/c^4)^1/2

 

rp = (hc)/(4πmpc^2)

 

mpc^2 = 3 * mec^2 * ln(4π) * 5 * ln(rp/rK) * RZ(5)

 

Where rp is the proton wavelength, mp is the proton mass, me is the electron mass, RZ is a Riemann zeta function. The other constants are standard physics constants.

 

The electron has a max log strain of the fine structure:

 

rK = (3/10 * 8πGKe^2/c^4)^1/2

 

re = (hc)/(4πmec^2)

 

2hc/(2πKe^2) = 5 * (re/rK)

 

Where re is the electron wavelength, h is the Planck constant, c the speed of light, K the electric constant, e the elementary charge.

 

In both 5 represents radius divided by radius to the fifth power.


Edited by devin553344, 23 December 2019 - 03:34 AM.