I am trying to find the concentration of glucose in a solution that has multiple different sugars in it. I want to create a suspension with a mashed up banana, and find the concentration of glucose within this suspension.
Ive been looking at many different things, such as using a titration of benedicts solution, but I believe that this will show the concentration of other sugars such as fructose and sucrose (https://www.techknow...using_titration)
or using Potassium Permanganate to find the time it takes for a solution with know concentrations of Glucose and interpolate the concentration of the unknown by using the amount of time it takes to discolor the Potassium Promanganate. (https://www.academia...n?auto=download) The issue is, I cannot find definitive information on whether or not these things work on only glucose or multiple sugars.
Any help is appreciated.
If you take Potassium Promanganate, Glucose,Water, and Sodium Hydroxide you will get a redox reaction that is highly exothermic however it should only react with Glucose, if you accurately measure the amount of MnO2 created by this reaction you should be able to measure the sugar content but be very careful or you could hurt yourself. This is a method but a possibly very dangerous method due to the amount of heat created in the redox reaction of those four. Another method could be to measure the heat then reverse engineer the exothermic part of this reaction, if you find the ΔE or Q of the reaction then you could also find out how much glucose reacted, if glucose is your limiting reactant. First, react a certain amount of sugar let's say a gram of sugar then measure the temperature change then that will yield the temperature release of a gram of sugar, then react your banana then it will tell you the amount of sugar within the banana by the heat release of that reaction ,if you divide the heat of the banana release by the gram of sugar release it will yield of many grams of sugar the banana contains. Qbanana/(QGram of sugar /GramSugar)= GramBanana or Q/(Q/M) = M
Edited by VictorMedvil, 03 September 2019 - 09:15 AM.