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Wormhole Metric Continued.


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#1 VictorMedvil

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Posted 11 April 2019 - 11:09 PM

I have decided to continue my Quaternionic Equation from the original Wormhole Metric Thread = https://www.sciencef...his-screwed-up/

 

This is mainly to check all the variables in the differential Equation to make sure that they all solve correctly and to make sure the Quaternion is anomaly free and solve the equation for (x,y,z,t,ωsp,M,I,k,φ,S,X,Z,μ,Y,q,a,β)

 

 

∇'(x,y,z,t,ωsp,M,I,k,φ,S,X,Z,μ,Y,q,a,β) = (d2/((ħ /(2Erest/C2)) 3a =1 (d2/d((C2/Erest)Ni = 1 MiRi)2) + (1/2)3a,β = 1  μ(PΠa)(Pβ - Πβ) + U - (ħ2/2)3N-6s=1(d2/dq2) + V)((|(Log(DgDaDψDφ-W)(((2ħGC2))Rs - (1/4)FaμvFaμv + i(ψ-bar)γμ(((Lghost QE  - gfabc(δμ (c-bar)a)Aμbcc) / (c-bar)aδμca) + ig(1/2)τWμ + ig'(1/2)YBμ)ψi +(ψ-bar)iLVijφψjr + (aji) - (μ2((φ-Dagger)φ) + λ((φ-Dagger)φ)2)/-(((Lghost QE   - gfabc(δμ (c-bar)a)Aμbcc) / (c-bar)aδμca) + ig(1/2)τWμ + ig'(1/2)YBμ)2)|)-e2S(r,t)/h)) - ((Erest/C2)ωs((((8πGTab/C4) + Λgab  - Rab) * gab-1))1/2 + (S/ (((3G(Erest/C2))/2C2Rs3)(RpVp) + (GIs/C2Rs3)((3Rp/Rs2)(ωRp) -ωp ))))Rs2/2))) / (ħ2/2(Erest/C2))))1/2(((1-(((2(Erest/C2)G / Rs) - (Isωs((((8πGTab/C4) + Λgab  - Rab) * gab-1))1/2 + (S/(((3G(Erest/C2))/2C2Rs3)(RpVp) + (GIs/C2Rs3)((3Rp/Rs2)(ωRp) -ωp )))))/2(Erest/C2))+ (((8πG/3)((g/(2π)3)∫(((Erelativistic2 - Erest2 / C2((Ar(X) + (ENucleon binding SNF εμ/mu) - Ar(XZ±)/Z) / mu)2)(1/2)(1/e((ERelativistic  - μchemical)/TMatter)±1)(ħω + ħωs) - ((ksC2)/ Rs2) + (((8πGTab/C4) + Λgab  - Rab) * gab-1))1/2(ΔxKiloparsec)))2/(C2)))1/2)

 

(d2/∇') - (Ctp) = ds2

https://www.wolframalpha.com/input/?i=(d%5E2+%2F+%E2%88%87%27)+-+(C+t)%5E2

 

(Universe Volumetric Planck State @ size of universe in radius) =(4/3)π((RUniverse/(tpC))Luniverse

https://www.wolframa... ((R/(t C)) )^3

https://www.wolframa... π ((R/(t C))^3

 

Luniverse = (Charge,∇Color,∇flavour,∇gravity  - ∇Dark Energy)

https://www.wolframalpha.com/input/?i=%E2%88%87+d

https://www.wolframa...i=(∇ g) - (∇ d)

 

Charge possible states per point (1,2/3, 1/3, 0,-1/3,-2/3,-1)

 

Color Possible states per point(R,B,G,0,antiG,antiB,antiR)

 

Flavour possible states per point (I,II,III,0,darkIII,darkII,darkI)

 

Gravity/Dark Energy possible states per point of space (Energy,Mass,Spin,0,-spin,-mass,-Energy)

 

Atleast the graphing equation and Equivalence principal are in working order having A.I. do the work.


Edited by VictorMedvil, 14 April 2019 - 03:02 AM.


#2 VictorMedvil

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Posted 14 April 2019 - 04:08 AM

I have decided to use this equation for a proton instead of the entire universe as it would be too much data to ever complete.

 

(Universe Volumetric Planck State @ size of universe in radius) =(4/3)π((RUniverse/(tpC)) (Charge,∇Color,∇flavour,∇gravity  - ∇Dark Energy)

 

 

 

 RUniverse = RProton = 10-15 meters 

 

The Equation Yields a Planck State of 9.9023511969154288921026543960449 * 1059 (Charge,∇Color,∇flavour,∇gravity  - ∇Dark Energy)

 

So a Field with 9.9023511969154288921026543960449 * 1059 cubes that are a Planck length  with states of (+1/(dx + dy +dz),R/(dx + dy +dz),I/(dx + dy +dz), (0/(dx + dy +dz) - 0/(dx + dy +dz),938.28/(dx + dy +dz)- 0/(dx + dy +dz),1/2/(dx + dy +dz)- 0/(dx + dy +dz))) , (+1/(dx + dy +dz),B/(dx + dy +dz),I/(dx + dy +dz), (0/(dx + dy +dz) - 0/(dx + dy +dz),938.28/(dx + dy +dz)- 0/(dx + dy +dz),1/2/(dx + dy +dz)- 0/(dx + dy +dz))) , (+1/(dx + dy +dz),G/(dx + dy +dz),I/(dx + dy +dz), (0/(dx + dy +dz) - 0/(dx + dy +dz),938.28/(dx + dy +dz)- 0/(dx + dy +dz),1/2/(dx + dy +dz)- 0/(dx + dy +dz))) if the proton is at rest.

 

The Strong Nuclear Force or color Map will look something like this which is the only thing over the 3-D field that varies in a proton.

 

download.jpg

 

If the Proton is in motion let's say moving in a particle accelerator at 8 Tev then the State is 7.6171932283964837631558879969576 * 1057 (+1/(dx + dy +dz),R/(dx + dy +dz),I/(dx + dy +dz), (8000000/(dx + dy +dz) - 0/(dx + dy +dz),938.28/(dx + dy +dz)- 0/(dx + dy +dz),1/2/(dx + dy +dz)- 0/(dx + dy +dz))) , (+1/(dx + dy +dz),B/(dx + dy +dz),I/(dx + dy +dz), (8000000/(dx + dy +dz) - 0/(dx + dy +dz),938.28/(dx + dy +dz)- 0/(dx + dy +dz),1/2/(dx + dy +dz)- 0/(dx + dy +dz))) , (+1/(dx + dy +dz),G/(dx + dy +dz),I/(dx + dy +dz), (8000000/(dx + dy +dz) - 0/(dx + dy +dz),938.28/(dx + dy +dz)- 0/(dx + dy +dz),1/2/(dx + dy +dz)- 0/(dx + dy +dz))) 

 

All of the Information being within the equation with a smaller color field of the same picture being less Planck Lengths within the particle due to length contraction.

 

download.jpg

 

The Graphing Equation displays all possible properties of the particle or substance to an qauntized amount of a Planck Length being exact without error, I could write the entire Tensor for each substance but it would take the big number amount of states. These were done assuming Dark Energy was not existent and a non expanding universe which are the zero terms. There is only one unknown in these equations which is the Spin number of Dark Energy particles being the final zero in the spin term, the graph is over d/dx + d/dy  + d/dz the big number shows the number of planck lengths that the fields manifest for a proton at rest versus in motion for these examples.

 

This shows this equation to be in working order and accurate to reality.

 

This equation is actually more complex than the long equation as it gives a single state for everything rather than a large number of multiple Planck States like this one.


Edited by VictorMedvil, 14 April 2019 - 05:01 AM.


#3 VictorMedvil

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Posted 15 April 2019 - 02:33 AM

If you wanted more detail of the Quarks within the Proton you could graph the equation with the same set of coordinates including the quarks with the same result.

 

For the Rest proton with quarks in finer detail.

 

9.9023511969154288921026543960449 * 1059  (+2/3/(dx + dy +dz),R/(dx + dy +dz),I/(dx + dy +dz), (0/(dx + dy +dz) - 0/(dx + dy +dz),938.28/(dx + dy +dz)- 0/(dx + dy +dz),1/2/(dx + dy +dz)- 0/(dx + dy +dz))) , (+2/3/(dx + dy +dz),B/(dx + dy +dz),I/(dx + dy +dz), (0/(dx + dy +dz) - 0/(dx + dy +dz),938.28/(dx + dy +dz)- 0/(dx + dy +dz),1/2/(dx + dy +dz)- 0/(dx + dy +dz))) , (-1/3/(dx + dy +dz),G/(dx + dy +dz),I/(dx + dy +dz), (0/(dx + dy +dz) - 0/(dx + dy +dz),938.28/(dx + dy +dz)- 0/(dx + dy +dz),1/2/(dx + dy +dz)- 0/(dx + dy +dz)))

 

Now the charges varies given the details of the quarks within the proton which as now the charges vary you will have two varing graphs one for the Strong Nuclear Force or Color and one for the Electromagnetic Force or Charge being the (+2/3/(dx + dy +dz),R/(dx + dy +dz))  + (+2/3 /(dx + dy +dz), B/(dx + dy +dz)) + (-1/3/(dx + dy +dz), G/(dx + dy +dz)) = (+1/(dx + dy +dz),RGB/(dx + dy +dz))

 

Charge Map

images.jpg

 

Color Map

download.jpg

 

 The equation can be used to whatever detail you would like it to be this being a more exact map of the proton next would be to add gluons if you wanted or even more protons and neutrons to construct an atom, but it is always exact to the planck length, no matter what detail is used.

 

Overlapped Charge and Color Map, (+2/3/(dx + dy +dz),R/(dx + dy +dz))  + (+2/3/(dx + dy +dz), B/(dx + dy +dz)) + (-1/3/(dx + dy +dz), G/(dx + dy +dz)) = (+1/(dx + dy +dz),RGB/(dx + dy +dz))

 

 

155531750110379283-1.jpg

 

Which solves perfectly making the graphing equation even physically correct next we will try something more challenging like a Feynman diagram using this equation, it should be able to graph anything in the universe to the planck length is the test.


Edited by VictorMedvil, 15 April 2019 - 03:07 AM.