So would you agree with Orion's statement that two participants engaged in constant relative velocity age at the same rate?

Orion didn’t say anything. All Orion does is copy and paste something with no thought of his own.

He made no attempt to answer your question.

Now you have stated, " The age difference will be one year at the turnaround point and one more year at the finish, for a total of 2 years difference." This is what it may look like if you consider time dilation and age difference as being the same thing but there's no math proof for this being the actual way age difference unfurls.

Unfortunately, it's a long slog to see all the math that supports this argument. This is why I got kicked off. No one knows math, not even high school algebra, and I got very frustrated by that fact.

You have not shown any math. All you have done is posted a lot of words and almost all of it is wrong.

The math is not difficult at all.

For distance contraction just use the familiar Lorentz factor:

[math]Y=\sqrt {1- \frac { v^(2) }{ c^(2) } } [/math]

When v = 0.6 c the factor is 0.8 so the distance the traveler goes is 3 lyr*0.8 = 2.4 lyr

At a velocity of 0.6c, the time taken by the traveler is 2.4 lyr / 0.6c = 4 years

The twin left behind on earth sees the traveler covering 3 lyr at 0.6 c so the time he experiences is 3 lyr /0.6 c = 5 years

The difference in ages for the outward trip is one year

And exactly the same thing happens on the return trip so the traveler ages 8 years while the twin on earth ages 10 years

The fact that they are monitoring the Doppler shift cannot have any effect on this result.

The only thing it can do is change the apparent way the twins perceive the relative ages during the trip but even then, their perceptions must agree with this final result.

With regards to the relativistic Doppler shift Z,

That is calculated this way: [math]Z=\sqrt { \frac { 1+v/c }{ 1-v/c } }[/math]

The relativistic Doppler shift for a spaceship that is approaching is the inverse of the shift for a ship that is receding.

For v = 0.6c, Z = 2 approaching and 0.5 receding.

So, the correct answer to the question you posed is:

outward trip: time dilation factor 0.8, Doppler shift 0.5, permanent age difference 1 year

inbound trip: time dilation factor 0.8, Doppler shift 2, permanent age difference 1 year

Only the permanent effects are cumulative so the total age difference is 2 years

The traveler ages 8 years while the earth twin ages 10 years.

If you are getting something else as your answer, you are wrong and that is why you have been getting kicked off of other forums.

But don’t worry, you won’t get kicked off of this one.

The moderation theme here is the more crackpots the merrier!

So I'm afraid you're incorrect in your statement that age difference jumps right after the turnaround.

I have not said anything to indicate that the age difference "jumps" anywhere.