Vmedvil Posted November 12, 2017 Report Share Posted November 12, 2017 (edited) Its right here in this equation. Secondly, I imagine it would stack here. Okay, Final Solution it is perfect this time I had forgotten parts of it several times, if p = 2, q = 1 then C *- 691.641346728 being the solution for the set as D-branes are p = 2 which means you would be going 207,348,859,390.017377424 meters per second exactly or .000006719718892405765773 parsecs per second which is about .00001519704745830918364158588 ly per second and strangely it doesn't violate anything in this universe as all the C's in that equation dilate by the same amount. E8 = ∇Eb(t,k,m,R,M,I,x,y,z) = ∇(1/((1-(((2MbG / Rs) - (IsωA2/2Mb)+V)2/C2))1/2))MbC2 E8 = ∇Eb(t,k,m,R,M,I,x,y,z) = ∇(1/((1-(((2MbG / Rs) - (IsωB2/2Mb)+V)2/C2))1/2))MbC2 Then L ≈ m Where ω2 = k2 + m2 Programming that equation was annoying which is in killing form making it a E8 as ∇ * L = 0 Edited November 13, 2017 by Vmedvil Super Polymath 1 Quote Link to comment Share on other sites More sharing options...
Vmedvil Posted November 22, 2017 Report Share Posted November 22, 2017 (edited) Okay, Final Solution it is perfect this time I had forgotten parts of it several times, if p = 2, q = 1 then C *- 691.641346728 being the solution for the set as D-branes are p = 2 which means you would be going 207,348,859,390.017377424 meters per second exactly or .000006719718892405765773 parsecs per second which is about .00001519704745830918364158588 ly per second and strangely it doesn't violate anything in this universe as all the C's in that equation dilate by the same amount. E8 = ∇Eb(t,k,m,R,M,I,x,y,z) = ∇(1/((1-(((2MbG / Rs) - (IsωA2/2Mb)+V)2/C2))1/2))MbC2 E8 = ∇Eb(t,k,m,R,M,I,x,y,z) = ∇(1/((1-(((2MbG / Rs) - (IsωB2/2Mb)+V)2/C2))1/2))MbC2 Then L ≈ m Where ω2 = k2 + m2 Programming that equation was annoying which is in killing form making it a E8 as ∇ * L = 0 This was found to be still too simple not taking account for variables, In any case, also it does not merge with Dubblesoix's equation like I thought being different SU(n) Groups this is discussion is finished please refer to http://www.scienceforums.com/topic/30658-a-type-of-gravitational-schrodinger-equation-and-the-minimum-distance-vs-the-phase-space/ for dubblesiox's stuff and I have to rework my equation found to not be invariant still as I had originally thought, Sorry Dubblesiox for the Hijack past the first couple of posts. Edited November 22, 2017 by Vmedvil Quote Link to comment Share on other sites More sharing options...
Shustaire Posted November 29, 2017 Report Share Posted November 29, 2017 Your using your E8 tensor wrong. Here is the Calculus rules on tensors https://arxiv.org/pdf/1603.01660.pdf Quote Link to comment Share on other sites More sharing options...
Vmedvil Posted December 13, 2017 Report Share Posted December 13, 2017 (edited) Your using your E8 tensor wrong. Here is the Calculus rules on tensors https://arxiv.org/pdf/1603.01660.pdfI know I was I was trying to find a way to absorb Dubblesoix's equation back then for Hillbert space. Continued here to a solution http://www.scienceforums.net/topic/111607-wormhole-metric-how-is-this-screwed-up/ Edited January 7, 2018 by Vmedvil Quote Link to comment Share on other sites More sharing options...
Vmedvil Posted December 21, 2017 Report Share Posted December 21, 2017 Fitting into EFE ab form or vice versa. k2 = K = (1/2)R Quote Link to comment Share on other sites More sharing options...
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