Jump to content
Science Forums

LaTeX update: Read this before posting!


Recommended Posts

  • 2 months later...

Just hijacking again, for a job purpose...:hihi:

 

[math]\Delta\vec{R}=\vec{R}(\vec{V}+\vec{I}\,)-\vec{R}(\vec{V})[/math]

 

[math]\Delta\vec{R}=\vec{R}(\vec{V}+\vec{I})-\vec{R}(\vec{V})[/math]

 

[math]f_{\rm c}=-\frac{\vec{R}\cdot\Delta\vec{R}}{\mid\Delta\vec{R}\mid^2}[/math]

 

[math]f_{\rm c}=-\frac{\vec{R}\cdot\Delta\vec{R}}{\mid\Delta\vec{R}\mid^2}[/math]

 

[math]\vec{V}[/math]

 

[math]\vec{V}[/math]

Link to comment
Share on other sites

  • 1 month later...
  • 1 month later...

I have just figured out that i have forgotten to tell you how to split equations over multiple lines... oooopsie :)

 

ok its very simple, for that we need to define a block called split like such:

\begin{split} - start of the block

\end{split} - end of the block

yes, please put in both beginning and end bits of this and don't be lazy

 

after that you can split ines by using \\

you can also align lines by a symbol by using an ampersand (&) in front of it

 

[math]

\begin{split}

\text{These Lines}&-\text{will be aligned}\\

\text{by the}&-\text{dash symbol}\\

&-\text{shazaam}\\

\text{boogie boogie} &-

\end{split}[/math]

 

similarly you can use = sign in equations, or whatever it is your heart desires :)

Link to comment
Share on other sites

  • 6 months later...

way bb works when it parses... if you do not want it to parse, use the noparse tags

[noparse][/noparse]

 

this way you can post

[math]m_{rel}=\frac{m_0}{\sqrt{1-\frac{v^2}{c^2}}}[/math]

which would render as

[math]m_{rel}=\frac{m_0}{\sqrt{1-\frac{v^2}{c^2}}}[/math]

 

 

ooh better yet

[math]\begin{split}\Delta P &= \frac{v}{c} \times \frac{E}{2c} \\

2\Delta P &= v\frac{E}{c^2} \\

P' &= Mv - 2\Delta P = \left(M-\frac{E}{c^2}\right)v \end{split}[/math]

:)

[math]\begin{split}\Delta P &= \frac{v}{c} \times \frac{E}{2c}\\ 2\Delta P &= v\frac{E}{c^2} \\ P' &= Mv - 2\Delta P = \left(M-\frac{E}{c^2}\right)v \end{split}[/math]

Link to comment
Share on other sites

  • 4 months later...
  • 5 months later...

Well actually lower case m denotes mass, thus the equivalence is not really valid, and even negating that, its a special case...

 

[math]\begin{split}E^2-(pc)^2&=(m_0c^2)^2\\E^2&=(m_0c^2)^2+(pc)^2\\E&=\sqrt{(m_0c^2)^2+(pc)^2}\\E&=c\times\sqrt{(m_0c)^2+p^2}\\\text{where } p=\gamma m_0v\\E&=c\times\sqrt{m_0^2c^2+\gamma ^2m_0^2v^2}\\E&=m_0c\times\sqrt{c^2+\gamma v^2}\end{split}[/math]

Link to comment
Share on other sites

  • 3 months later...
  • 9 months later...

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
×
×
  • Create New...